45

Once i have parsed a JSON String into a GSON provided JsonObject class, (assume that i do not wish to parse it into any meaningful data objects, but strictly want to use JsonObject), how am i able to modify a field / value of a key directly?

I don't see an API that may help me.

https://static.javadoc.io/com.google.code.gson/gson/2.6.2/com/google/gson/JsonObject.html

6 Answers 6

93

Strangely, the answer is to keep adding back the property. I was half expecting a setter method. :S

System.out.println("Before: " + obj.get("DebugLogId")); // original "02352"

obj.addProperty("DebugLogId", "YYY");

System.out.println("After: " + obj.get("DebugLogId")); // now "YYY"
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2 Comments

They should've called this putProperty. Would've made it more clear. It also doesn't state anything in the documentation that this replaces existing properties, but I guess it wouldn't be valid Json otherwise.
When I tried using the same addProperty method, it added an extra element with the same key but different value. Any work around that?
14

This works for modifying childkey value using JSONObject. import used is

import org.json.JSONObject;

ex json:(convert json file to string while giving as input)

{
    "parentkey1": "name",
    "parentkey2": {
     "childkey": "test"
    },
}

Code

JSONObject jObject  = new JSONObject(String jsoninputfileasstring);
jObject.getJSONObject("parentkey2").put("childkey","data1");
System.out.println(jObject);

output:

{
    "parentkey1": "name",
    "parentkey2": {
     "childkey": "data1"
    },
}

1 Comment

just wanted to emphasize the question is about com.google.gson.JsonObject and not org.json.JSONObject. The selected and most upvoted answer, at the bottom, seems to be correct
8

Since 2.3 version of Gson library the JsonArray class have a 'set' method.

Here's an simple example:

JsonArray array = new JsonArray();
array.add(new JsonPrimitive("Red"));
array.add(new JsonPrimitive("Green"));
array.add(new JsonPrimitive("Blue"));

array.remove(2);
array.set(0, new JsonPrimitive("Yelow"));

Comments

2

Another approach would be to deserialize into a java.util.Map, and then just modify the Java Map as wanted. This separates the Java-side data handling from the data transport mechanism (JSON), which is how I prefer to organize my code: using JSON for data transport, not as a replacement data structure.

2 Comments

Thanks, probably also the reason why there isn't a setter in the first place.
"remove()" - or add() again if you're using pre-version 2 (not sure of the exact version, but I've seen the difference between 1.2.3 and 2.2.4 APIs).
-1

It's actually all in the documentation.
JSONObject and JSONArray can both be used to replace the standard data structure.
To implement a setter simply call a remove(String name) before a put(String name, Object value).

Here's an simple example:

public class BasicDB {

private JSONObject jData = new JSONObject;

public BasicDB(String username, String tagline) {
    try {
        jData.put("username", username);
        jData.put("tagline" , tagline);
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

public String getUsername () { 
    String ret = null;
    try {
        ret = jData.getString("username");
    } catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
    } 
    return ret;
}

public void setUsername (String username) { 
    try {
        jData.remove("username");
        jData.put("username" , username);
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

public String getTagline () {
    String ret = null;
    try {
        ret = jData.getString("tagline");
    } catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
    } 
    return ret;
}

1 Comment

Wrong library. First I wondered where the hell you got a put() method, then I realized you said JSONObject, which is the json.org library, not JsonObject, the GSON version.
-2
public static JSONObject convertFileToJSON(String fileName, String username, List<String> list)
            throws FileNotFoundException, IOException, org.json.simple.parser.ParseException {
        JSONObject json = new JSONObject();
        String jsonStr = new String(Files.readAllBytes(Paths.get(fileName)));
        json = new JSONObject(jsonStr);
        System.out.println(json);
        JSONArray jsonArray = json.getJSONArray("users");
        JSONArray finalJsonArray = new JSONArray();
        /**
         * Get User form setNewUser method
         */
        //finalJsonArray.put(setNewUserPreference());
        boolean has = true;
        for (int i = 0; i < jsonArray.length(); i++) {
            JSONObject jsonObject = jsonArray.getJSONObject(i);
            finalJsonArray.put(jsonObject);
            String username2 = jsonObject.getString("userName");
            if (username2.equals(username)) {
                has = true;
            }
            System.out.println("user name  are :" + username2);
            JSONObject jsonObject2 = jsonObject.getJSONObject("languages");
            String eng = jsonObject2.getString("Eng");
            String fin = jsonObject2.getString("Fin");
            String ger = jsonObject2.getString("Ger");
            jsonObject2.put("Eng", "ChangeEnglishValueCheckForLongValue");
            System.out.println(" Eng : " + eng + "  Fin " + fin + "  ger : " + ger);
        }
        System.out.println("Final JSON Array \n" + json);
        jsonArray.put(setNewUserPreference());
        return json;
    }

1 Comment

Please format in eclipse or netbeans. I think it will be working well and get tour solutions.

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