multiple array return using ajax() on success : jquery

Question

hi friends i have an ajax()of jquery that parse the xml file , create array on success and want to return multiple array on callback is it possible if yes then how ? pls guide me guys. this is my example code .

var arr1= new Array();
var arr2=new Array();
 var var1,var2;
function parseData(callback){   
        var cnt=0;
            $.ajax({
                type:"GET",
                url:"test.xml",
                dataType: "xml",
                success:function(xml){

                    var tempcategory= new Array(2);
                    var tempitem=new Array(4);                  
                    var1= $(xml).find('var1').text();
                    var2= $(xml).find('var2').text();

                    $(xml).find('result').each(function(){
                    var Id = $(this).find('id').text();
                    var Name = $(this).find('name').text();
                        tempcategory[0]=catogoryId;
                        tempcategory[1]=catogoryName;
                        arr1[cnt]=tempcategory;
                        $('#output').append("<br/>"+categories[cnt]);
                         cnt++;
                    });                 
                             callback.call(null,var1);

                error: function(){
                     alert("An error occurred while processing XML file.");
                }
           });      

}

now in this code there is a line callback.call(null,var1);

In this i m returning only 1 variable but like that i have array and some other variable also how can i return that all array and variable togather and if not is there any other way to return multiple array.

thanks

pls ignore that this is just an example for better understanding — unkown
– unkown, Commented Jul 13, 2012 at 7:23

Inkbug · Accepted Answer · 2012-07-13 08:22:30Z

1

~~What you can do is:~~

callback.call( null, var1, var2 );

Also, see Harry's answer with the syntax problems in your code.

Note also that it is considered better form to use var arr1 = []; rather than var arr1 = new Array(), they are both equivalent but the first is shorter.

Edit: A much simpler way to do it would be to simply write callback( var1, var2 ). However, if you still want to use .call, see MDN for a full description.

Edit:

thnx for help and we can use it as mentioned in this answer callback.call( null, var1, var2, var3 ); and call the function with

fun_name(function (var1,var2,var3) {        
        alert(var1);
        alert(var2);
        alert(var3);        
    });

edited Jul 13, 2012 at 8:22

answered Jul 13, 2012 at 7:26

Inkbug

1,6931 gold badge11 silver badges29 bronze badges

Sign up to request clarification or add additional context in comments.

6 Comments

unkown Over a year ago

ok thnks let me try this i keep in mind the other thing u mentioned thnx

unkown Over a year ago

one more thing to ask can u pls write the syntax of callback.call() with paramenters

unkown Over a year ago

ok then how will i get this value can u tell me i m calling this function in this way when i pass single variable--> var total; parseData(function (x) { alert(x); });

unkown Over a year ago

can u show me any link or any thing to implement ur callback( var1, var2 )

Inkbug Over a year ago

What variables do you need to pass to the callback?

|

Hkachhia · Accepted Answer · 2012-07-13 07:23:44Z

1

Syntax error in your function I have corrected it Plz check it

function parseData(callback){   
var cnt=0;
    $.ajax({
        type:"GET",
        url:"test.xml",
        dataType: "xml",
        success:function(xml){
            var tempcategory= new Array(2);
            var tempitem=new Array(4);                  
            var1= $(xml).find('var1').text();
            var2= $(xml).find('var2').text();

            $(xml).find('result').each(function(){
            var Id = $(this).find('id').text();
            var Name = $(this).find('name').text();
                tempcategory[0]=catogoryId;
                tempcategory[1]=catogoryName;
                arr1[cnt]=tempcategory;
                $('#output').append("<br/>"+categories[cnt]);
                 cnt++;
            });                 
            callback.call(null,var1);
        },
        error: function(){
             alert("An error occurred while processing XML file.");
        }
   });      

}

answered Jul 13, 2012 at 7:23

Hkachhia

4,5478 gold badges44 silver badges79 bronze badges

1 Comment

unkown Over a year ago

pls ignore syntax only the thing i m asking how to return multiple array and varialbe in same as i have done in this callback.call(null,var1); is it possible

Collectives™ on Stack Overflow

multiple array return using ajax() on success : jquery

2 Answers 2

6 Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

6 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related