9

This code shows frm01:

$(document).ready(function() {
$("#reg").click(function () {
$("#frm01").show("slide", { direction: "down" }, 1000);
});
});

But I want to hide frm01 if it is allready visible, and vice versa. How could I do this, please ?

4 Answers 4

15

Try jQuery's toggle() method:

$(function() {
    $("#reg").click(function () {
        $("#frm01").toggle(1000);
    });
});

You don't need jQuery to use if-else statements; Javascript implements those natively...

$(function() {
    $("#reg").click(function () {
        if ($("#frm01").is(":visible"))
            $("#frm01").slideUp(1000);
        else
            $("#frm01").slideDown(1000);
    });
});
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Comments

2

try this:

$(document).ready(function() {
   $("#reg").click(function () {
    if ($("#frm01").is(':hidden')) {
      $("#frm01").show("slide", { direction: "down" }, 1000);
    } else {
      $("#frm01").hide(1000);
    }
  });
});

Comments

1
  $("#reg").on('click', function () {
    $("#frm01:hidden").show("slide", { direction: "down" }, 1000);
    $("#frm01:visible").hide("slide", { direction: "up" }, 1000);
  });

or

  $("#reg").toggle(
    function () {
      $("#frm01").show("slide", { direction: "down" }, 1000);
    },
    function(){
      $("#frm01").hide("slide", { direction: "up" }, 1000);
    }
  );

should also work

Comments

1

You can use $.toggle() method to show and hide. Some time need to identify whether elements are hide or show.

$("#reg").click(function () {
if($("#frm01").hasClass('fram1-slide-on')){
    $("#frm01").hide();
    $("#frm01").removeClass('fram1-slide-on');
}   else {
    $("#frm01").show("slide", { direction: "down" }, 1000);
    $("#frm01").addClass('fram1-slide-on');
}

});

Comments

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