Get Element using elementtree python

Question

My XML looks something like: (Sorry if duplicate question, but I'm not very experienced with XML so I have a bit trouble with the terminology

<sometags>
    <Value>
        <Scalar unitGlobalDataRef="Unit_0" unit="None" xmlns="xxxxyyyy">20</Scalar> 
    </Value>
</sometags>

Using this code:

element = ET.parse(fileName)
root = element.getroot()
for subelement in root:
    if (subelement.tag == "{xxyy}Parameter"):
        for value in subelement:
            for subval in value:
                #Here is where it prints
                if (subval.tag == "{xxxxyyyy}Scalar"):
                    print subval.tag
                    print subval.text
                    print subval.tail
                    print subval.attrib

prints

{xxxxyyyy}Scalar
0


{'unitGlobalDataRef': 'Unit_0', 'unit': 'None'}

How can I get the value 20 out from the element?

Edited with more of the code, hope it helps (can't post the whole code / XML without having to censor and rename a lot of stuff) — Viktor Mellgren
– Viktor Mellgren, Commented Jul 19, 2012 at 15:21
By the way, with lxml you can do root.findall('.//{xxxxyyyy}Scalar') for a recursive search. — Rodrigo Queiro
– Rodrigo Queiro, Commented Jul 19, 2012 at 15:28

ernie · Accepted Answer · 2012-07-19 16:31:07Z

1

subval.text should containt the information you're seeking. Since you're getting a 0, it implies that your iterations may be wrong, and you're getting a different element than you think you are. This is further reinforced by the fact that your attributes don't match.

answered Jul 19, 2012 at 16:31

ernie

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1 Comment

Viktor Mellgren Over a year ago

You are correct, somehow I must have failed with the printouts or something. Using if subval.text != "0" : print subval.text I found the correct values

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