Parsing String Java

Question

I got a String:

["4fd1cf1783353a15415","4ffecf87fcc40d110a965626"]

or

["4fd5f684815345","4fd6ef3e60a676854651","4fd83c33c19164512153"]

And I'd like to store every id (eg. 4fd5f684815345, 4fd6ef3e60a676854651, 4fd83c33c19164512153...) in a independant String (or ArrayList).

How to parse it, because the String can be dynamic (1,2,3 values or more)?

OR JSON Array Parsing:

My JSON

"idCards":[
"4fc52f95egvt418541515",
"4fd1d05454151541545115"
],

A part of my code:

msg3 = (JSONArray) myobject.get("idCards");
System.out.println(msg3.toJSONString());

The result:

[4fc52f95egvt418541515","4fd1d05454151541545115"]

I'd like this 2 values in 2 differents String.

Many thanks for your help!

You might wanna try regex, you can use delimiter to split 'em up. I am not quite sure about the code though. :) — praxmon
– praxmon, Commented Jul 20, 2012 at 9:45
Please clarify your question. You have a String array in that format? You have string data coming from a file or socket in that format? with the [ and ] and double-quotes? — user207421
– user207421, Commented Jul 20, 2012 at 9:47
This is a JSON data structure. The correct way to parse this is to use a JSON library. — HJW
– HJW, Commented Jul 20, 2012 at 9:47
You converted from a JSON String into a JsonArray, the next step is to convert this to a Java List. And you're done. I have modified my answer to show you. — HJW
– HJW, Commented Jul 20, 2012 at 9:57

HJW · Accepted Answer · 2012-07-20 10:02:28Z

4

It would appear to be that this could be a JSON String. In which case, you may make use of a Java JSON Library to help you parse that into Java native objects.

http://www.json.org/

http://code.google.com/p/google-gson/

String data = "[\"4fd5f684815345\",\"4fd6ef3e60a676854651\",\"4fd83c33c19164512153\"]";

// parse JSON String to JSON Array
JsonArray array = (JsonArray) (new JsonParser()).parse(data);

// build a Java ArrayList
List<String> stringList = new ArrayList<String>();

// for each item in JsonArray, add to Java ArrayList
for (int i = 0; i < array.size(); i++) {
    stringList.add((array.get(i)).getAsString());
}

edited Jul 20, 2012 at 10:02

answered Jul 20, 2012 at 9:44

HJW

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Comments

matt burns · Accepted Answer · 2012-07-20 10:03:26Z

2

I fully agree with the JSON answers, but if this is a one-off hack, you could just do this:

    String input = "[\"4fd5f684815345\",\"4fd6ef3e60a676854651\",\"4fd83c33c19164512153\"]";
    input = input.replace("[", "");
    input = input.replace("]", "");
    input = input.replace("\"", "");
    String[] parts = input.split(",");

edited Jul 20, 2012 at 10:03

answered Jul 20, 2012 at 9:50

matt burns

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1 Comment

dacwe Over a year ago

String.replace also replaces all occurrences so no need to use replaceAll.

nhahtdh · Accepted Answer · 2012-07-20 10:05:28Z

2

I make a number of assumptions here:

Assume no spaces before and after the delimiting [, ], ,
Assume no , and " character in the Strings you want to extract
```
input.substring(1, input.length() - 1).replaceAll("\\\"", "").split(",");
```
Or if you don't want to mess with regular expression (replaceAll function works with regular expression), then you can use replace method:
```
input.substring(1, input.length() - 1).replace("\"", "").split(",");
```

Due to the assumptions above, this answer is very brittle. Consider using JSON parser if the data is really JSON.

edited Jul 20, 2012 at 10:05

answered Jul 20, 2012 at 9:46

nhahtdh

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6 Comments

nhahtdh Over a year ago

@dacwe: Taken care of by the substring. Need to update the answer with assumption.

dacwe Over a year ago

Too fast, sorry, however, use replace instead of replaceAll when replacing non-regex.

nhahtdh Over a year ago

@dacwe: I really don't know: Can you remove character with replace?

dacwe Over a year ago

Yes you can, check it out.

nhahtdh Over a year ago

@dacwe: It is likely that it is implemented with Pattern class, though. OpenJDK does grepcode.com/file/repository.grepcode.com/java/root/jdk/openjdk/…

|

Pramod Kumar · Accepted Answer · 2012-07-20 09:51:06Z

1

    String str = "[\"4fd5f684815345\",\"4fd6ef3e60a676854651\",\"4fd83c33c19164512153\"]";
    String strArry[] = null;

    if(str.trim().length() > 0){
        str = str.substring(1 , str.length()-1).replaceAll("\\\"", "");
        strArry = str.split(",");
    }

answered Jul 20, 2012 at 9:51

Pramod Kumar

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Comments

roberto chiaretti · Accepted Answer · 2012-07-20 10:00:33Z

0

If s is the input string, it can just be as simple as

String[] idArray = s.replaceAll("[\\[\\]\"]", "").split(",");

answered Jul 20, 2012 at 10:00

roberto chiaretti

1

Comments

cl-r · Accepted Answer · 2012-07-20 10:16:45Z

it would be more secure (because ',' may be a decimal separator) to split with ("\",\""), and not remove trailing " in replaceAll, here subtring do not parse all the string :

final String str = "[\"4fd5f684815345\",\"4fd6ef3e60a676854651\",\"4fd83c33c19164512153\"]";

final String strArray[] = str.substring(2, str.length() - 2).split("\",\"");
final ArrayList<String> al = new ArrayList<String>();

for (final String string : strArray) {
    al.add(string);
    System.out.println(string);
}
System.out.println(al);

for (final String string : strArray) { System.out.println(string); }

Output :

4fd5f684815345
4fd6ef3e60a676854651
4fd83c33c19164512153
[4fd5f684815345, 4fd6ef3e60a676854651, 4fd83c33c19164512153]

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