Assigning a function to a string with the function's name in Python

Question

Let's say I have a function assigned to a variable, func. func contains the function itself (ie. print func returns <function func at 0x103f25410>

I have a simple class:

class Item():
    def __init__(self, data):
    # init code
        pass
    def func(self):
        pass
    def dunc(self):
        pass

Let's say in __init__ I received func in data and can access it as data.func. I could assign that to consume by self.consume = data.func.

But what if I had a dictionary of functions in data?

{"func" : <function func at 0x103f25410>, "dunk" : <function dunk at 0x103f25410>}

Is there anyway I could do something like self.key = data[key]? In other words, assign func and dunc with the data in the dictionary but not explicitly have to self.func or self.dunc every assignment?

icktoofay · Accepted Answer · 2012-07-21 05:11:52Z

2

If I understand your question correctly, you could do something like:

def __init__(self, data):
    for name, func in data.items():
        setattr(self, name, func)

Then, you can refer to self.func or self.dunc (or whatever else was in data).

edited Jul 21, 2012 at 5:11

icktoofay

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answered Jul 21, 2012 at 5:03

Greg Hewgill

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1 Comment

Greg Hewgill Over a year ago

You're welcome, sorry about the confusion on the setattr() call. I blame this flu I've got. :)

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