Can anyone help me passing char array to method when i tried it is only copying one index value so
char c1[]={0x01};
char c2[]={0x02};
char c3[]={0x03};
char *c[3];
c[0] = c1;
c[1] = c2;
c[2] = c3;//if i pass this char array to the below method only c[0] is copied
char* arrrr =[self mountLVparams:NULL :c :code_ward_arr];
//my method being this
-(char *)mountLVparams:(signed char *)initData :(char *)obj :(signed char *)codeWard
c is a pointer to a pointer. your method signature should be like -(char *)mountLVparams:(signed char *)initData :(char **)obj :(signed char *)codeWard
char c1[]={0x01};
char c2[]={0x02};
char c3[]={0x03};
char *c[3];
c[0] = c1;
c[1] = c2;
c[2] = c3;//if i pass this char array to the below method only c[0] is copied
char* arrrr =[self mountLVparams:NULL :c :code_ward_arr];
-(char *)mountLVparams:(signed char *)initData :(char **)obj :(signed char *)codeWard
{
int i;
for(i=0;i<3;++i)
printf("%d----%c", i,*obj[i]);
}
-(char *)mountLVparams:(signed char *)initData :(char **)obj[3] :(signed char *)codeWardlike this when i call this method i m getting Incompatible pointer types sending 'char *[3]' to parameter of type 'char *' this warning
I have one solution by passing array to your function and then creating char *
const char c1[]={0x01};
NSString *s1 = [[NSString alloc] initWithCString:c1 encoding:NSUTF8StringEncoding]; //convert into string
const char c2[]={0x02};
NSString *s2 = [[NSString alloc] initWithCString:c2 encoding:NSUTF8StringEncoding]; //convert into string
const char c3[]={0x03};
NSString *s3 = [[NSString alloc] initWithCString:c3 encoding:NSUTF8StringEncoding]; //convert into string
NSArray *arr = [NSArray arrayWithObjects:s1,s2,s3,nil]; // adding all strings
[s1 release];
[s2 release];
[s3 release];
Now function would be like this where u will pass arr(NSArray):
-(char *)mountLVparams:(signed char *)initData :(NSArray *)arrChars :(signed char *)codeWard
{
int count = [arrChars count];
char *cargs = (char *) malloc(sizeof(char) * (count + 1));
//cargs is a pointer to 4 pointers to char
int i;
for(i = 0; i < count; i++) {
NSString *s = [arrChars objectAtIndex:i];//get a NSString
const char *cstr = [s cStringUsingEncoding:NSUTF8StringEncoding];//get cstring
int len = strlen(cstr);//get its length
char *cstr_copy = (char *) malloc(sizeof(char) * (len + 1));//allocate memory, + 1 for ending '\0'
strcpy(cstr_copy, cstr);//make a copy
cargs[i] = cstr_copy;//put the point in cargs
}
cargs[i] = NULL;
NSLog(@"%c | %c| %c ",cargs[0],cargs[1],cargs[2]);
return cargs;
}
Credit for creation of char from array of string goes to @yehnan follow objective-c nsarray to c array
Use like this:
char *cs = [self mountLVparams:(your arguments here and pass array here)];
NSLog(@"%c | %c | %c",cs[0],cs[1],cs[2]);
perhaps, you would be looking for the following where you can pass the NSString object with the desired content as parameter:
NSString *_string = [NSString stringWithString:@"\x01\x02\x03"];
[self yourMethod:_string];
and inside the -yourMethod:
- (void)yourMethod:(NSString *)stringWithChars {
char _ch = [stringWithChars characterAtIndex:1]; // it gives back you an unsigned short but in this case you can use this value as char without any problem
NSLog(@"chat at index #1 : %d, %c", _ch, _ch); // or do whatever you'd like to do.
}
parameter c is the pointer pointing to your character array. The pointer will point the first address of the array hence it is by default c[0].
You can pass it as NSstring. [NSString stringWithFormat:%s,c].
