editing json string in php

Question

I am trying to edit a data query using php by passing it through javascript,

my ajax request looks like

var totalSearchResult=10;
$.ajax({
    url:"php/queryManipulation.php",
    type: 'POST',
    data: { totalQuery : totalSearchResult,  query : '{"data":{"match_all":{}}}'},

    success: function(finalList)
    {
        alert(finalList);
    }
});

my php code looks like

<?php
$from=$_POST["totalQuery"];
$qry=json_decode($_POST["query"]);
$qry->from=$from;   }?>

I am trying to get it in the form,

{"data": {"match_all": {}} , "from": 10}

I get the error Object of class stdClass could not be converted to string

You forgot to json_encode it back?

Alvin Wong
– Alvin Wong

2012-07-24 08:34:01 +00:00
Commented Jul 24, 2012 at 8:34 — Alvin Wong
– Alvin Wong, Commented Jul 24, 2012 at 8:34
And why I'd see an extra } at the end of your PHP script?

Alvin Wong
– Alvin Wong

2012-07-24 08:36:58 +00:00
Commented Jul 24, 2012 at 8:36 — Alvin Wong
– Alvin Wong, Commented Jul 24, 2012 at 8:36

Ignas · Accepted Answer · 2012-07-24 08:43:57Z

3

Edit: Changed json_decode return value from array to object

You need to encode the json again just after finishing the edits. So what you can do is something like:

<?php
    $from            = $_POST["totalQuery"];
    $qry             = json_decode($_POST["query"]);
    $qry->data->from = $from;
    //you will get the new json string 
    //as the finalList variable in your post callback
    echo json_encode($qry); 
?>

edited Jul 24, 2012 at 8:43

answered Jul 24, 2012 at 8:35

Ignas

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2 Comments

user1371896 Over a year ago

I get it in the form {"data":{"match_all":[]},"from":"10"}... It should be like{"data":{"match_all":{}},"from":"10"}

Ignas Over a year ago

I've changed the answer. Try now.

Piter · Accepted Answer · 2012-07-24 08:34:11Z

0

You should use json_decode($string, true) - so it will be an array. Details here: http://php.net/manual/en/function.json-decode.php

answered Jul 24, 2012 at 8:34

Piter

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Comments

knittl · Accepted Answer · 2012-07-24 08:34:43Z

0

You can decode to an array (not sure about objects) and re-encode:

$qry = json_decode($_POST['query'], TRUE);
$qry['from'] = 10;
$new_qry = json_encode($qry);

answered Jul 24, 2012 at 8:34

knittl

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