php: iterate through function arguments by key value

Question

I have a php function function foo($bar1, $bar2, $bar3)

Is there a possibility to get the parameter names and values dynamically?

I found func_get_args (http://php.net/manual/de/function.func-get-args.php) but that will return something like

0 => "valueOf$bar1", 1=> "valueOf$bar2", 2 => "valueOf$bar3"

What I want instead is something like:

"$bar1" => "valueOf$bar1", "$bar2"=> "valueOf$bar2", "$bar3" => "valueOf$bar3"

Is that possible?

Short answer: no. If you want to pass key/value pairs, use an array or an object. Long(er) answer: Yes it is possible using reflection or get_defined_vars() and stripping out all the superglobals - but don't. — DaveRandom
– DaveRandom, Commented Jul 27, 2012 at 10:13
... and is pointless. Function parameter names are irrelevant to PHP (still). — Narf
– Narf, Commented Jul 27, 2012 at 10:20

Shakti Singh · Accepted Answer · 2012-07-27 10:18:03Z

5

You can use get_defined_vars. An example

answered Jul 27, 2012 at 10:18

Shakti Singh

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2 Comments

soulmerge Over a year ago

Hadn't thought of that, but this means you get all defined parameters, not just the actual arguments that were passed, i.e. you will have the default values of omitted parameters in the resulting array.

DaveRandom Over a year ago

@soulmerge As long as you give all arguments a default of NULL, this shouldn't matter as isset() will still return FALSE. You could always array_filter() if you want to strip them completely.

soulmerge · Accepted Answer · 2012-07-27 11:28:23Z

2

It can be achieved, but involves a lot of effort. You would need to get the parameter names via reflection and map the names to the values retrieved via func_get_args.

If you really need this, you can take another, simpler route and define that your function takes a single parameter object:

class MyParamObj {
    public $foo;
    public $bar;
}

function myfunc(MyParamObj $args) {
    # ...
}

edited Jul 27, 2012 at 11:28

answered Jul 27, 2012 at 10:16

soulmerge

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1 Comment

Horen Over a year ago

this is a good answer that would work. @Shatki Singh's answer was more what I was looking for though

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