Powershell Switch Statement to Set Multiple Variables

Question

I am in the process of converting some old VB script to Powershell. I am trying to use a Switch statement to set multiple variables. Is this possible in Powershell? In VBS my code would look something like this:

Select Case ENV
    Case "DEV"
        : SRCDRV  = "\\Server1" _
        : DESTDRV = "\\Server1\Folder1\"

    Case "TEST"
        : SRCDRV  = "F:" _
        : DESTDRV = "\\Server1\Folder2\"

    Case "PROD"
        : SRCDRV  = "F:" _
        : DESTDRV = "\\Server2\Folder2\"
End Select

I have tried something similar in PS, but it doesn't seem to set the variables.

switch ($cENV) {
    DEV { 
        $SRCDRV = "\\Server1"
        $DSTDRV = "\\Server2\Folder1\"
        break     
    }
    TEST {
        $SRCDRV = "\\Server1"
        $DSTDRV = "\\Server2\Folder2\"
        break
     }
    PROD {
        $SRCDRV = "\\Server1"
        $DSTDRV = "\\Server2\Folder2\"
        break
     }
}

When I check the value of either DESTDRV or SRCDRV I get an error saying: The variable '$SRCDRV' cannot be retrieved because it has not been set. Any ideas on what I'm doing wrong?

Dan Atkinson · Accepted Answer · 2018-01-24 11:42:19Z

13

Your code works when a case is found for the switch. $cENV probably has a value that does not match "DEV", "TEST", or "PROD". Add a default switch case and do something when you don't have a match, example:

switch ($cENV) {
  DEV { 
    $SRCDRV = "\\Server1"
    $DSTDRV = "\\Server2\Folder1\"
    break     
  }
  TEST {
    $SRCDRV = "\\Server1"
    $DSTDRV = "\\Server2\Folder2\"
    break
  }
  PROD {
    $SRCDRV = "\\Server1"
    $DSTDRV = "\\Server2\Folder2\"
    break
  }
  default {
    throw "No matching environment for `$cENV: $cENV"
  }
}

edited Jan 24, 2018 at 11:42

Dan Atkinson

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answered Jul 30, 2012 at 19:37

dugas

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Comments

Chris N · Accepted Answer · 2012-07-30 19:38:16Z

11

Are you setting $cENV first?

I'm running that exact script above like this:

$cENV = "DEV"
switch ($cENV) {
    DEV { 
        $SRCDRV = "\\Server1"
        $DSTDRV = "\\Server2\Folder1\"
    }
    TEST {
        $SRCDRV = "\\Server1"
        $DSTDRV = "\\Server2\Folder2\"
     }
    PROD {
        $SRCDRV = "\\Server1"
        $DSTDRV = "\\Server2\Folder2\"
     }
}
$SRCDRV

And it's returning

\\Server1

answered Jul 30, 2012 at 19:38

Chris N

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2 Comments

dugas Over a year ago

$cENV probably has some value, otherwise he would get an error message that $cENV cannot be retrieved.

mack Over a year ago

Thanks, you're right, if I set $cENV to "DEV" it does return the correct value. I didn't think to try setting it specifically. The $cENV variable is being set by a function that determines the script file's location. If I put the switches, "DEV", "TEST" and "PROD", in quotation marks, it works like a champ. Thanks very much for your help!

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