javascript simple Regex

Question

Hi for the below javascript I want a regex which will replace all instances of left square bracket with \Left square bracket ,right square bracket with \ plus right square bracket or full stop with a \ dot

<script type="text/javascript" type="text/javascript">

        $(document).ready(function () {
            var someId = '#Something[0].AnotherSelected[5].Validator';

            alert(s);
        });

    </script>

Your description of what you want doesn't match your example. You don't want to replace those characters with double slash, you want to prefix them with double slash. — Barmar
– Barmar, Commented Aug 1, 2012 at 10:46
your right barmar i have updated question to match. I want a regex which will replace all instances of left square bracket with \\Left square bracket ,right square bracket with \\ right square bracket or full stop with a \\ dot — Somedeveloper
– Somedeveloper, Commented Aug 1, 2012 at 10:49

Mitya · Accepted Answer · 2012-08-01 10:47:27Z

3

var str = 'something[.something]].something[';
console.log(str.replace(/[\[\]\.]/g, '\\\\'));

Outputs

something\\\\something\\\\\\something\\';

[EDIT - based on the OP's comment below:

console.log(str.replace(/[\[\]\.]/g, function($0) { return '\\\\'+$0; }))

edited Aug 1, 2012 at 10:47

answered Aug 1, 2012 at 10:26

Mitya

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1 Comment

Somedeveloper Over a year ago

thats close but i want to keep the square brackets but just put a \\ in front of it so i want str= #Something\[0\].AnotherSelected\[5\]\\.Validator

Dmytro Mindra · Accepted Answer · 2012-08-01 10:57:36Z

2

First we need a regular expression that matches '[',']' and '.' globally.
This regular expression looks like this:

 /(\[|\]|\.)/g

Then we replace each occurence with \\ concatenated with matched substring $&

var someId  = "#Something[0].AnotherSelected[5].Validator";
var newstr  = someId.replace(/(\[|\]|\.)/g, "\\\\$&")
alert(newstr)

The output is

 #Something\\[0\\]\\.AnotherSelected\\[5\\]\\.Validator

You can test it on jsfiddle

edited Aug 1, 2012 at 10:57

answered Aug 1, 2012 at 10:46

Dmytro Mindra

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Comments

arnoudhgz · Accepted Answer · 2012-08-01 10:25:22Z

0

someId = someId.replace(/\[/g, "\\\\[").replace(/\./g, "\\\\.");

edited Aug 1, 2012 at 10:25

answered Aug 1, 2012 at 10:19

arnoudhgz

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2 Comments

Rob W Over a year ago

That's an invalid regular expression.

arnoudhgz Over a year ago

of course, but stackoverflow didn't display all my characters. So I've edited it.

Barmar · Accepted Answer · 2012-08-01 10:44:20Z

0

someId = someId.replace(/[][.]/g, '\\\\$&');

answered Aug 1, 2012 at 10:44

Barmar

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