How to declare string array in c

Question

#include<stdio.h>

int main()
{
int i;
string A[]={"Ahmet", "Mehmet", "Bulent", "Fuat"};

for(i=0;i<=3;i++){
printf("%s",A[i]);
}
return 0;
}

How can i see my array's elements as output?

Compiler says "'string' undeclared".

Beware that input characters as your ü in "Bülent" may not show up as just one char as you C compiler understands it. — Jens Gustedt
– Jens Gustedt, Commented Aug 2, 2012 at 11:30

ouah · Accepted Answer · 2012-08-02 09:37:11Z

22

This way:

 char *A[] = {"Ahmet", "Mehmet", "Bülent", "Fuat"};

A is an array of pointers to char.

answered Aug 2, 2012 at 9:37

ouah

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1 Comment

cethint Over a year ago

Thanks for your help. Basic structure, but it can not been remembered easily.

Gilad Green · Accepted Answer · 2017-08-06 11:17:09Z

6

const char *A[] = {"Ahmet", "Mehmet", "Bülent", "Fuat"};

If you don't include the const, it will work but the compiler will give you annoying warnings unless you suppress them with "-w".

edited Aug 6, 2017 at 11:17

Gilad Green

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answered Nov 14, 2016 at 4:20

Ron Tackaberry

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Comments

askmish · Accepted Answer · 2012-08-02 09:50:19Z

1

In C, a string can only be represented, as an array of characters.So, to represent an array of strings you have to make array of (array of characters). In C++ we have a STL called, string and you can make an array of string and use it in the the way you have written(ofcourse with modifications to C specific stuff in your code).

answered Aug 2, 2012 at 9:50

askmish

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Comments

Mhammed Talhaouy · Accepted Answer · 2022-03-04 22:41:25Z

0

you can use cs50 library to work with string or you can work with pointers.

CS50

string names[] = {"Mohammed", "Mhammed", "Ali", "Lora"};

pointer

char *names[] = {"Mohammed", "Mhammed", "Ali", "Lora"};

answered Mar 4, 2022 at 22:41

Mhammed Talhaouy

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