Syntax and Variables in PHP

Question

I'm having some trouble with writing some syntax. I want to echo this

'location_1' => $location_1,

However, it is not as simple as it seems. When I write the echo statement the integer 1 must be the variable $z. Here is the code I attempted to write

echo "'location_' . $z . '' =>' . ${'location_' . $z} . ','";

This is what it outputted

'location_' . 1 . '' =>' . something . ','

$location_1 is equal to the string something. I'm lost at how to do this the right way. Any guides on describing how this syntax works would be a major help too so I can understand it completely.

Musa · Accepted Answer · 2012-08-05 03:53:42Z

2

You can just write variables directly into double quoted strings see http://www.php.net/manual/en/language.types.string.php#language.types.string.parsing

echo "'location_$z' => \$location_$z,";

You might want to also read the rest of the strings doc

answered Aug 5, 2012 at 3:53

Musa

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Oussama Jilal · Accepted Answer · 2012-08-05 03:48:31Z

1

This is the link to the echo documentation (see the examples, I think they described well how it works)

answered Aug 5, 2012 at 3:48

Oussama Jilal

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Debashis · Accepted Answer · 2012-08-05 03:58:16Z

1

You can break it into two lines and get the expected output.

For example:

$var_location = "$". "location". $z;

echo "'location_" . $z . "' =>'" . $var_location . "','";

edited Aug 5, 2012 at 3:58

answered Aug 5, 2012 at 3:53

Debashis

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tigrang · Accepted Answer · 2012-08-05 04:01:38Z

1

One way is: echo "'location_{$z}' => \$location_{$z},";

Edit: Is this what you meant?

<?php
$z = 1;
$location_1 = 'something';
echo "'location_$z' => " . ${'location_'. $z} . ',';

which produces: 'location_1' => something,

Why don't you store these variables inside an array for easier access. Something like:

$locations = array('location_id' => 'location_name');

edited Aug 5, 2012 at 4:01

answered Aug 5, 2012 at 3:48

tigrang

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Alex Kalicki · Accepted Answer · 2012-08-05 04:18:32Z

1

Here's one way:

echo "'location_$z' => \$location_$z,";

You need to escape the $ symbol. The double quotes represent the thing to echo in this case, whereas the single quotes actually get echoed.

edited Aug 5, 2012 at 4:18

answered Aug 5, 2012 at 3:48

Alex Kalicki

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