How to convert object to JSON in symfony2

Question

I am using this:

    $users = $em->getRepository('UserBundle:User')->getallUsers($search);
    $response = new Response(json_encode($users));
    $response->headers->set('Content-Type', 'application/json');
    return $response;

Users are multiple entities not single result.

But I am getting this:

[{},{},{},{},{},{}]

I want something like:

[ { label: $user.getName(), value: $user.getId() }, ... ]

How can i do that?

EDIT: I also tried json_encode($users->toArray()) then I get this error:

Call to a member function toArray() on a non-object

Which version of symfony do you use?

Vitalii Zurian
– Vitalii Zurian

2012-08-08 05:55:23 +00:00
Commented Aug 8, 2012 at 5:55 — Vitalii Zurian
– Vitalii Zurian, Commented Aug 8, 2012 at 5:55

Inoryy · Accepted Answer · 2012-08-08 06:34:49Z

6

You need to have a way to serialize your objects, you can't expect json_encode to magically guess which fields are allowed to be encoded.

A good bundle I recommend for this task is JMSSerializerBundle. Make sure you read through documentation carefully before using it!

End result will probably look like this:

$users = $em->getRepository('UserBundle:User')->getallUsers($search);
$response = new Response($container->get('serializer')->serialize($users, 'json'));

answered Aug 8, 2012 at 6:34

Inoryy

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5 Comments

Mirage Over a year ago

I already jave JMSSerializerBundle installed but i get this error You have requested a non-existent service "serializer". how can i declrae the service for JMS

Mirage Over a year ago

it is there in jms vendor and its latest version

AdrienBrault Over a year ago

You have to register the bundle in your app/AppKernel.php

Boun Over a year ago

You can try : $serializer = $this->container->get('serializer'); $response = new Response($serializer->serialize($users, 'json'));

Hunt Over a year ago

@Inoryy you miss the $this before container

ludriv · Accepted Answer · 2013-04-28 11:57:21Z

0

Try {{ your_variable|raw }}

Sorry for late

answered Apr 28, 2013 at 11:57

ludriv

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1 Comment

Croll Over a year ago

Well this is the best easy method, but it is not automatic and requires implementing __toString() function in a class, which returns json_serialize(array(..)) product.

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