Quick question: It's kind of tough to describe so let me just show an example.
Is there anyway to do this: (I'm using jQuery but this is a general javascript question)
$('div.element').offset().x;
$('div.element').offset() by itself will return {'x' : 30, 'y' : 180}, so I'm just wondering if there is any compact way of doing this without creating an extra variable.
Thanks! Matt
As you said, you can absolutely use this:
$('div.element').offset().left
OR
$('div.element').offset().top
Please note that jQuery's offset() returns { left: 30, top: 180 } not an x/y pair like you said.
It will always create the object. I think you mean .top or .left instead of x/y?
>>> $('#jq-header').offset().left // 177.5
var coords = $('#jq-header').offset()
coords.left // 177.5
coords.top // 0
alert($('body').offset().left) // 0
Apparently, you can do the exact thing you said: $('div.element').offset().x;.
