java lang NumberFormatException

Question

I am trying to convert string to double. But i am getting the number format exception. The code that gives the exception is like this:

double B = Double.parseDouble(s);

I take the s value from server to my application. And it is like this:

fd485b154a0427fa75c0428cdafac71f

Any solution?

fd485b154a0427fa75c0428cdafac71f is the number in which base? — Jigar Joshi
– Jigar Joshi, Commented Aug 8, 2012 at 7:42
@JigarJoshi I guess hex... As there is no dot or comma, I guess it is an integer number (not int though, much too high) — brimborium
– brimborium, Commented Aug 8, 2012 at 7:45

Kumar Vivek Mitra · Accepted Answer · 2012-08-08 07:49:33Z

2

1. Double.parseDouble() works only on Double Numbers , Not on non-Numbers.

2. fd485b154a0427fa75c0428cdafac71f is NO Number......

answered Aug 8, 2012 at 7:49

Kumar Vivek Mitra

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Vivek · Accepted Answer · 2012-08-08 07:50:59Z

1

Try this: (i am assuming the string is HEX coz of the 0-9 & a-f in it)

double doubleVal = new BigInteger("fd485b154a0427fa75c0428cdafac71f", 16).longValue();
long longVal = new BigInteger("fd485b154a0427fa75c0428cdafac71f", 16).longValue();
System.out.println(doubleVal);
System.out.println(longVal);

This gives:

8.4848548707027374E18
8484854870702737183

answered Aug 8, 2012 at 7:50

Vivek

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Matin Kh · Accepted Answer · 2012-08-08 07:55:55Z

1

Double.parseDouble(s) is doing just fine if s is number. Apparently you are receiving the number in hex base. Right?

It's simple as this:

double doubleAsLongReverse = new BigInteger(doubleAsString, 16).longValue();

answered Aug 8, 2012 at 7:55

Matin Kh

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J.K · Accepted Answer · 2012-08-08 07:45:10Z

0

double B = Double.parseDouble(s);

Which is works only for numbers not for such fd485b154a0427fa75c0428cdafac71f values example String s = "123"; double B = Double.parseDouble(s); System.out.println(B);

answered Aug 8, 2012 at 7:45

J.K

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martijno · Accepted Answer · 2012-08-08 07:49:35Z

0

Use Hex in Apache's Commons Codec.

answered Aug 8, 2012 at 7:49

martijno

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Alexey Ogarkov · Accepted Answer · 2012-08-08 07:49:58Z

0

You can use ByteBuffer class http://docs.oracle.com/javase/7/docs/api/java/nio/ByteBuffer.html You can put bytes from string s.getBytes() and then call getDouble()

Hope it helps.

answered Aug 8, 2012 at 7:49

Alexey Ogarkov

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Peter Lawrey · Accepted Answer · 2012-08-08 08:11:33Z

0

I would use

double doubleVal = new BigInteger("fd485b154a0427fa75c0428cdafac71f", 16).doubleValue();
System.out.println(doubleVal);

prints

3.366703756933705E38

If you use .longValue() you will be chopping off the start of the number due to an overflow.

answered Aug 8, 2012 at 8:11

Peter Lawrey

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