How to I return JSON in flask python fetched from another url to the browser?

Question

I want to use flask to return JSON to the brower with or without simplejson (with appropriate headers) here is what I have so far for my flask application:

@app.route('/')
def hello_world():
    QUERY_URL="http://someappserver:9902/myjsonservlet"
    result = simplejson.load(urllib.urlopen(QUERY_URL))
    return result;

Assuming the JSON output returned is:

{"myapplication":{"system_memory":21026160640.0,"percent_memory":0.34,
"total_queue_memory":4744,"consumers":1,"messages_unacknowledged":0,
"total_messages":0,"connections":1}

When I visit the page http://localhost:5000 however, I get a Internal Server Error. What must I do with "result" to get it to display appropriately? Or is there some way I can tell it to return with json headers?

When I add a print statement to print the result I can see the JSON, but in the browser it gives me an Internal Server Error.

linkyndy · Accepted Answer · 2013-11-30 14:58:45Z

10

import requests
r = requests.get(QUERY_URL)
return r.json

#normal return
return jsonify(username=g.user.username,
               email=g.user.email,
               id=g.user.id)

jsonify is available in flask. Here is the docs

edited Nov 30, 2013 at 14:58

linkyndy

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answered Aug 8, 2012 at 18:06

Kracekumar

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