PHP - Regular expression - number matching before specific character

Question

I have this kind of string:

1234567890(number without specific number of character)-(minus symbol serves as divider)text

How can I see and extract number before - symbol?

lll · Accepted Answer · 2012-08-14 09:16:54Z

4

Use a regex like this:

preg_match('/^(\d+)/', '123-something', $match);

This will capture all decimal digits from the start of the string until the first non-decimal digit, and the result will be in the $match variable.

if (preg_match('/^(\d+)/', $string, $match)) {
    $number = $match[1];
}

answered Aug 14, 2012 at 9:16

lll

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Comments

Bhuvan Rikka · Accepted Answer · 2012-08-14 09:25:15Z

2

Use preg_split()

$bla=preg_split('#(?<=\d)-(?=[a-z])#i', "1234567890-asdlkj");
echo $bla[0];

gives 1234567890

If you want the text field,you can use

echo $bla[1];

gives asdlkj

answered Aug 14, 2012 at 9:25

Bhuvan Rikka

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