Differences between JSONLint and PHP JSON_DECODE

Question

In the code below, the JSON in the $datastring variable passes as valid JSON on JSONLint.

However, I get Syntax error when using PHP's json_encode.

What can I do to fix this? I've tried stripping the slashes but get same error.

$datastring = '[{"Program": 3034370,"Column": "CLI_RID","Value": "1006278"},{"Program": 3034370,"Column": "Filename","Value": "\\\\henery\\1006278\\CONFIRMATION LETTER AVAILABLE.html"},{"Program": 3034370,"Column": "EVENT_CODE","Value": "20120725ZZAQ"},{"Program": 3034370,"Column": "DOC_NAME","Value": "Confirmation Email"},{"Program": 3034370,"Column": "PrintDate","Value": "20120410"},{"Program": 2959623,"Column": "ISSUE","Value": "Res Spring"},{"Program": 2959623,"Column": "FILENAME","Value": "~/Res/Mag.aspx?I=res_spring&P=1006278"}]';
$data = json_decode($datastring, true);

// Define the errors.
$json_errors = array(
    JSON_ERROR_NONE => 'No error has occurred',
    JSON_ERROR_DEPTH => 'The maximum stack depth has been exceeded',
    JSON_ERROR_CTRL_CHAR => 'Control character error, possibly incorrectly encoded',
    JSON_ERROR_SYNTAX => 'Syntax error',
);

if(!$data) {
echo 'Last error : '. $json_errors[json_last_error()]. PHP_EOL. PHP_EOL;
} else {
echo print_r($data, true);
}

I will be getting this JSON string from an ASP.Net page.

phihag · Accepted Answer · 2012-08-14 19:42:57Z

3

If you write out a string in a php literal constant, you'll have to double all the slashes. So when the original JSON is something like:

{"foo": "backslash: \\"}

The corresponding php string literal is:

$json = '{"foo": "backslash: \\\\"}';

answered Aug 14, 2012 at 19:42

phihag

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2 Comments

MB34 Over a year ago

The backslashes are ALREADY doubled.

phihag Over a year ago

No they're not. The code contains the php literal '"\\\\henery\\1006278\\CONFIRMATION LETTER AVAILABLE.html"', which is the string "\\henery\1006278\CONFIRMATION LETTER AVAILABLE.html". In JSON, backslashes in strings must be escaped, and \1 is an invalid literal.

Ignacio Vazquez-Abrams · Accepted Answer · 2012-08-14 19:42:13Z

0

You need more backslashes, not fewer; PHP strips one level itself since you're using it in a string literal.

answered Aug 14, 2012 at 19:42

Ignacio Vazquez-Abrams

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4 Comments

Ignacio Vazquez-Abrams Over a year ago

@MB34: IT NEEDS TO BE QUADRUPLED.

MB34 Over a year ago

Can't do that with addslashes because it will add them to the quotes as well.

MB34 Over a year ago

The string is going to be coming from ASP, as I noted above.

Ignacio Vazquez-Abrams Over a year ago

Then the code in the question is inaccurate, since it shows it in a string literal.

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