JSON object does not want to initialize

Question

Hello I am trying to create a JSON object using some values I take from a form. For some reson the code isn't working. I triple checked all the names f the inputs so you can assume they are correct. I did isolate the problem to the line where I instantiate my JSON object:

    function createJSON()
    {
        if (document.forms["formIn"]["gender"][0].checked == true)
        {
            var g= "male";
        }
        else if (document.forms["formIn"]["gender"][1].checked == true)
        {
            var g= "male";
        }
        var jsonobj={"name":document.forms["formIn"]["name"].value, "surname":document.forms["formIn"]["surname"].value, "email":document.forms["formIn"]["email"], "dob":document.forms["formIn"]["dob"].value, "password":document.forms["formIn"]["password"].value, "cpassword":document.forms["formIn"]["confirm_password"].value, "gender":g}
        var jsonstr=JSON.stringify(jsonobj);
        alert(jsonstr);
        var newjobj=JSON.parse(jsonstr);
        alert(newjobj.email);
    }

Thanks for everyones help. I just didn't have a .value after my email. Cleared alot of other stupid mistakes aswell, but still my second alert only says [object] [object].

Any errors in your JavaScript console? If you isolated it down to one line, why did you show us the rest of the code? — Matt Ball
– Matt Ball, Commented Aug 21, 2012 at 19:37
any reason why not matter what gender you select... you are always male? ;-) — scunliffe
– scunliffe, Commented Aug 21, 2012 at 19:40
I'm not sure which part isn't working? stringify and alerting the string? or parsing and alerting the email? What exactly isn't working as you expected? — thescientist
– thescientist, Commented Aug 21, 2012 at 19:43

BLSully · Accepted Answer · 2012-08-21 19:54:36Z

1

Please try this:

function createJSON()
{
    var g = "unknown",
        jsonobj,
        jsonstr,
        newjobj;

    if (document.forms["formIn"]["gender"][0].checked == true)
    {
        g = "male";
    }
    else if (document.forms["formIn"]["gender"][1].checked == true)
    {
        g = "female";
    }
    jsonobj={"name":document.forms["formIn"]["name"].value, "surname":document.forms["formIn"]["surname"].value, "email":document.forms["formIn"]["email"], "dob":document.forms["formIn"]["dob"].value, "password":document.forms["formIn"]["password"].value, "cpassword":document.forms["formIn"]["confirm_password"].value, "gender":g}
    jsonstr=JSON.stringify(jsonobj);
    alert(jsonstr);
    newjobj=JSON.parse(jsonstr);
    alert(newjobj.email);
}

answered Aug 21, 2012 at 19:54

BLSully

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Comments

aug · Accepted Answer · 2012-08-21 19:40:09Z

0

You are missing a ; at the end of where you instantiate your JSON object. Everything else seems to be okay though.

answered Aug 21, 2012 at 19:40

aug

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2 Comments

James M Over a year ago

Semicolons are usually optional in JavaScript.

aug Over a year ago

Hmm that's true... I would also like to see the error message he gets in the console as Matt Ball pointed out so if the OP could post that, it'd be a lot more helpful.

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