I have been using to get my files
<?php include 'example.html'; ?>
however how do you get them if they are in a subfolder: For example
pictures/example.html
-
1Why would you include an image?Waleed Khan– Waleed Khan2012-08-22 15:30:27 +00:00Commented Aug 22, 2012 at 15:30
-
I'm guessing that the image file name in the question is just an example, and that it could be extended to any file type (such as other *.php files)Chris Forrence– Chris Forrence2012-08-22 15:57:19 +00:00Commented Aug 22, 2012 at 15:57
-
Yeh sorry I didnt mean to put .jpg I will edit it nowuser1616846– user16168462012-08-24 10:56:24 +00:00Commented Aug 24, 2012 at 10:56
Add a comment
|
4 Answers
It should be just as easy as
<?php
include('pictures/face.jpg');
?>
Comments
The best practice for this is to define a ABSOLUTE_PATH constant that contains the directory that everything is located under. After that, you can simply copy and paste everything, because it is defining the 'full' path, which doesn't change from directory to directory.
E.g
define("ABS_PATH", $_SERVER['DOCUMENT_ROOT']);
or
define("ABS_PATH", dirname(__FILE__));
// This defines the path as the directory the file is in.
Then at any point you can simply do this to include a file
include(ABS_PATH . "/path/to/file");
1 Comment
Elias Van Ootegem
A note of warning when using
$_SERVER: It returns "The document root directory under which the current script is executing, as defined in the server's configuration file.", so in some cases might not be entirely what you'd expect it to beAll you need to do is include it like this:
<?php
include('pictures/face.jpg');
?>
But why are you trying to include an image? This should be done through HTML.
Comments
If it were a source file, you could do:
include __DIR__ . '/pictures/src.php';
But because you're dealing with a binary file (raw data, ones and zeros) you may want to use the image library:
$resource = imagecreatefromjpeg( string $filename );
See http://www.php.net/manual/en/function.imagecreatefromjpeg.php
Or, if you just want the bytes, use:
$contents = file_get_contents(__DIR__ . '/pictures/src.php');
