Convert float to integer in Python - invalid literal error

Question

How do I convert this number to an integer I can do simple math with?! (eg. 10.5200 below.)

{"bid":["10.52000000","0.70824000"],"ask":["10.54000000","2.07336000"],"seq":2456916}

I get the following error, and it's driving me mental:

ValueError: invalid literal for int() with base 10: '10.52'

This is what I'm running:

bitfl = json.loads(bitfl)
bid = bitfl['bid']
ask = bitfl['ask']
bidd = bid[0] #edit - this is actually in, as it's a list
askk = ask[0]
print('diff: %i' % (int(bidd[0]) - int(askk[0])))

I don't know WHY it should be so difficult to just accept "10.52" as a string or float or unicode and just convert it to a normal, calculable integer!

Any help MUCH appreciated!

10.52 is obviously not a valid integer. Convert to float and then to int. — JBernardo
– JBernardo, Commented Aug 25, 2012 at 2:20

ThiefMaster · Accepted Answer · 2012-08-25 02:18:43Z

4

The problem is that you are trying to convert a string containing a non-integer to an integer.

The easiest/best solution is using int(float(yourstring))

Since you receive the data as JSON you should also consider requiring whatever client is providing the data not to use strings for non-string data.

answered Aug 25, 2012 at 2:18

ThiefMaster

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2 Comments

BrenBarn Over a year ago

@KnutOle: What about them? If you want an integer you need to get rid of the decimals, since integers are whole numbers.

Tjorriemorrie Over a year ago

You still get ValueError: could not convert string to float: - Am I missing something?

Nasir · Accepted Answer · 2012-08-25 02:34:55Z

1

Simply write int(float(bidd[0]))

answered Aug 25, 2012 at 2:34

Nasir

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