Passing value from inside of function to a parameter in JavaScript

Question

I have a function that replaces characters from a string

function ratko(a) {
    var k = a.toString();
    var z = k.replace(/\,/g, '], [');
    var s = z.replace(/\./g, ', ');
    var final = "[[" + s + "]]";
    alert(final);
}

What I need is to get the value of final outside the function like this:

var outsideValue = final;

EDIT!!! --

function ratko() gets it's value from ajax

success: function (data) {
if (data.success) {
alert("Note: This month has " + data.holidays.length + " holidays.");
praznici = data.holidays;
ratko(praznici);
}
else {
alert(data.ErrorMessage);
}

"gets it's value from ajax". Something tells me it is yet another case of ignoring A in AJAX. — Oleg V. Volkov
– Oleg V. Volkov, Commented Aug 27, 2012 at 9:23
I've made jsFiddle - jsfiddle.net/cj4Er You can see the problem. I need "holiDays" to get the value of "Globalna" — R.App
– R.App, Commented Aug 27, 2012 at 9:36

JohnB · Accepted Answer · 2012-08-27 08:55:09Z

1

Possibility 1:

function ratko (a) {
   ...
   return final;
}

var outsideValue = ratko (...);

Possibility 2:

var final;
function ratko (a) {
   // no var final declaration here
   ...
}
...
ratko (...);
// now final has the value assigned to it in the function

You can access variables declared in an outer scope in an inner scope, which is what you do in Possibility 2.

answered Aug 27, 2012 at 8:55

JohnB

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1 Comment

R.App Over a year ago

Thank you JohnB but that does not solver my issue. I still get "undefined".

cih · Accepted Answer · 2012-08-27 08:57:55Z

0

One option would be to use a global variable, just declare it outside of the function.

var myvar = 1;
function myFunction()
   alert(myvar); // 1
}

You can read more on javascript variables here.

answered Aug 27, 2012 at 8:57

cih

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Comments

Samson · Accepted Answer · 2012-08-27 09:18:54Z

0

You declare it outside the function scope:

  var finalVar;

function ratko(a) {
var k = a.toString();
var z = k.replace(/\,/g, '], [');
var s = z.replace(/./g, ', ');
 finalVar= "[[" + s + "]]";
alert(finalVar);
}

var outsideValue = finalVar;

Beware final is a reserved keyword in Javascript. I changed its name. Besides that, keep in mind that Javascript is always parsed from top to bottom. So using a variable before declaring it will definitely give you an undefined.

edited Aug 27, 2012 at 9:18

answered Aug 27, 2012 at 8:52

Samson

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3 Comments

R.App Over a year ago

What I did was this: var final; function ratko(a) { var k = a.toString(); var z = k.replace(/\,/g, '], ['); var s = z.replace(/\./g, ', '); final = "[[" + s + "]]"; } var outsideValue = final; document.write(outsideValue); And it gives me "undefined";

JohnB Over a year ago

Where do you call the function?

R.App Over a year ago

I've made jsFiddle - jsfiddle.net/cj4Er You can see it here. What I need is "holiDays" to get the value of "Globalna"

alessio271288 · Accepted Answer · 2012-08-27 20:36:00Z

0

you must be modify your function code like this

function ratko(a) {
  var k = a.toString();
  var z = k.replace(/\,/g, '], [');
  var s = z.replace(/./g, ', ');
  var final = "[[" + s + "]]";
  //alert(final); comment this code line and replace this with the code above
  return final;
}

after you can call your function ratko with this simple code

var inputValue = 'simple message';
var parsedValue = ratko(inputValue);

you find the final value into a new variable parsedValue

edited Aug 27, 2012 at 20:36

answered Aug 27, 2012 at 9:07

alessio271288

3581 silver badge7 bronze badges

7 Comments

R.App Over a year ago

Again sir, on document.write(parsedValue) i get "undefined"

alessio271288 Over a year ago

but your alert return "undefined"? in this case the problem is the function... another question is if you use the document.write under the call at the function or in another context

R.App Over a year ago

No, the alert giver me everything fine, but the document.write - doesn't

alessio271288 Over a year ago

you use the document.write under the call at the function or in another context?

R.App Over a year ago

no, outside of the function. I use it for sole purpose to see if my variable gets the data.

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