int[] array = new int[10];
array[0] = 1;
array[1] = 1;
array[2] = 1;
array[3] = 2;
array[4] = 1;
array[5] = 2;
array[6] = 1;
array[7] = 1;
array[8] = 2;
array[9] = 3;
I want to get this result:
1 => 6 times
2 => 3 times
3 => 1 times
Is there any simple way to get this result without if-else statement?
Thanks.
Yes, by using LINQ's GroupBy():
var res = array.GroupBy(x => x)
.Select(x => new {Number=x.Key,Times=x.Count()})
.ToList();
Note:
ToList() may not be necessary if you want to iterate over the result just once.
GroupBy ;-)You can use LINQ and group the data:
var result = array.GroupBy(x => x)
.Select(x => new { Value = x.Key, Count = x.Count() });
array.GroupBy(a => a).Select(a => new { Value = a.Key, Count = a.Count() });
You can use Linq to calculate the results. If you put the following in a Console Application it should work:
using System;
using System.Linq;
namespace ConsoleApplication
{
class Program
{
static void Main(string[] args)
{
int[] array = new int[10];
array[0] = 1;
array[1] = 1;
array[2] = 1;
array[3] = 2;
array[4] = 1;
array[5] = 2;
array[6] = 1;
array[7] = 1;
array[8] = 2;
array[9] = 3;
var group = from i in array
group i by i into g
select new
{
g.Key,
Sum = g.Count()
};
foreach (var g in group)
{
Console.WriteLine(g.Key + " " + g.Sum);
}
}
}
}
This is a Linq statement that will allow you to build your output:
array.GroupBy(x => x).Select(x => new { x.Key, Count = x.Count() } );
Enumerable.GroupBy groups a sequence by a selector. Then you can use the groups to count them or do whatever you need.
var countGroups = array.GroupBy(a => a)
.OrderByDescending(g => g.Count());
foreach(var g in countGroups)
Console.WriteLine("{0} => {1} times", g.Key, g.Count());
Here's a demo with your sample: http://ideone.com/WatNL
if-elsestatement to get the result at all! :-)