Convert String to Int. String value = scanner input.....hard to explain

Question

Okay so i'm trying to convert a couple things.

So i have already converted my Scanner to a String, now what I want to do is, take the value that they input and use it as an integer for a couple else if statements. IT WONT WORK!

Here is my code so far:

import java.util.Scanner;
public class apples {
public static void main(String args[]) {

    Scanner fname = new Scanner(System.in);
    Scanner sname = new Scanner(System.in);
    Scanner number = new Scanner(System.in);
    tuna weight = new tuna();

    System.out.println("Enter Your First Name: ");
    String fname1 = fname.nextLine();
    String fnames = fname1;

    System.out.println("Enter Your Last Name: ");
    String sname1 = sname.nextLine();
    String snames = sname1;

    System.out.println("Enter Your Weight (Lbs.) : ");
    String num = number.nextLine();
    String num1 = num;

    System.out.println("Okay " + fname1 + " " + sname1
            + " I can see here that you weigh " + num + "lbs.");
    int num2 = num1.parseInt();
    if (num1 >= 275)
        System.out
                .println("You know, you should maybe consider laying off the candy my friend.....");
}

}

As a general comment you don't need three scanners. You would get the same results if you used one scanner and called it three times. This would also mean that you wouldn't have the similar variable names of fname being a scanner and fname1 being a string — n00begon
– n00begon, Commented Aug 29, 2012 at 23:26

Reimeus · Accepted Answer · 2015-02-17 11:01:11Z

5

You should use an argument in parseInt:

int num2 = Integer.parseInt(num1);

and

if (num2 >= 275) 
...

edited Feb 17, 2015 at 11:01

answered Aug 29, 2012 at 23:10

Reimeus

160k16 gold badges225 silver badges282 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

iSully Over a year ago

Thanks a ton man! I was using the parseInt but didnt know about the (num1); part. Thanks again!

Ossie7 · Accepted Answer · 2012-08-29 23:13:47Z

2

Try this:

try{
  num2 = Integer.parseInt(num1);
}
catch(Exception ex) {
  System.out.println("Something went wrong, the string could not be converted to int.");
}

the try-catch is pretty important because the string could contain characters that cannot convert to int, ofc you need to catch it better than this, but keep it in mind

answered Aug 29, 2012 at 23:13

Ossie7

3703 silver badges9 bronze badges

1 Comment

MadProgrammer Over a year ago

+1 for the exception handling (although I'd prefer a ParseException ;))

Sivaraman · Accepted Answer · 2012-08-30 11:57:09Z

0

You can use other type scanner method also to get the int value

num = number.nextInt();

answered Aug 30, 2012 at 11:57

Sivaraman

717 bronze badges

Comments

NanoPixel · Accepted Answer · 2018-07-19 04:05:04Z

0

Here is what I did:

Scanner input = new Scanner(System.in);
System.out.println("Type number");
int number = input.nextInt();
System.out.println(number);

Hope this helps...

answered Jul 19, 2018 at 4:05

NanoPixel

1328 bronze badges

Comments

Muhammad Shaeel Abbas · Accepted Answer · 2015-08-27 16:09:54Z

-1

I'm not a pro in Java myself but I tweaked your code up a notch to get it working. Here it is. Glad if it helps.

p

ackage APPLE;
import java.util.Scanner;
public class apples {
public static void main(String args[]) {

    Scanner fname = new Scanner(System.in);
    Scanner sname = new Scanner(System.in);
    Scanner number = new Scanner(System.in);
    Scanner intScanner = new Scanner(System.in);

    System.out.println("Enter Your First Name: ");
    String fname1 = fname.nextLine();
    String fnames = fname1;

    System.out.println("Enter Your Last Name: ");
    String sname1 = sname.nextLine();
    String snames = sname1;

    System.out.println("Enter Your Weight (Lbs.) : ");
    int num = intScanner.nextInt();


    System.out.println("Okay " + " " + fname1 + " " + sname1 
            + " I can see here that you weigh " + num + "lbs.");

    if (num > 275){
        System.out.println("You know, you should maybe consider laying off the candy my friend.....");
    }
}
}

answered Aug 27, 2015 at 16:09

Muhammad Shaeel Abbas

295 bronze badges

1 Comment

MarsAtomic Over a year ago

What's the purpose of answering a question that was both asked and satisfactorily answered three years ago? And to top it off, you didn't even bother to explain the changes you made that caused you to consider it "up a notch."

Collectives™ on Stack Overflow

Convert String to Int. String value = scanner input.....hard to explain

5 Answers 5

1 Comment

1 Comment

Comments

Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

5 Answers 5

1 Comment

1 Comment

Comments

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related