How to dynamically add to a JavaScript object?

Question

I can't seem to figure out how to get the following results...

var errors;
errors = { username: "username_error", email: "email_error" };

...when looping through data in this code:

var errors = {}
$.each(data,function(k,v)
{
   errors[k] = v; // doesn't seem to work
});

It does produce an object yet in a different format.

EDIT: console log.

Expected results:

Object
email: "email_error"
username: "username_error"
__proto__: Object
 edit:25
Object
__proto__: Object

Generated results:

Object
email: Array[1]
0: "email_error"
length: 1
__proto__: Array[0]
username: Array[1]
0: "username_error"
length: 1
__proto__: Array[0]
__proto__: Object

@FrankieTheKneeMan: data is a JSON object. k and v are strings. — MarkL
– MarkL, Commented Sep 1, 2012 at 0:48
... Right. Can you do a console.log(data) and put that here? — FrankieTheKneeMan
– FrankieTheKneeMan, Commented Sep 1, 2012 at 0:51
STILL don't know what the hell is in data! PLEASE do a console.log(data). It will help us eliminate the easy fixes. — FrankieTheKneeMan
– FrankieTheKneeMan, Commented Sep 1, 2012 at 0:59

pedrofurla · Accepted Answer · 2012-09-01 01:00:49Z

2

By the results you posted with the log output, it seems the objects in data are arrays. Try replacing the assignment with this:

errors[k] = v.length>0 ? v[0] : ""

answered Sep 1, 2012 at 1:00

pedrofurla

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3 Comments

MarkL Over a year ago

indeed it was an array. v[0] worked. I hate mjself for literally wasting hours on this :) thank you.

pedrofurla Over a year ago

all you had to do was a console.log(data), the console is your friend, use it...

MarkL Over a year ago

the funny thing is... I was using it but I was just too blind to notice the array type.

The Alpha · Accepted Answer · 2012-09-01 01:01:16Z

1

Try this

var errors = {}
$.each(data,function(k,v)
{
   errors[k] = v[0];

});

DEMO.

answered Sep 1, 2012 at 1:01

The Alpha

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