php shell_exec doesn't work with imagemagick commands

Question

I try to convert a rgb color to transparent

When i use this code in the command line, it works perfect.

convert -transparent 'RGB(249,249,255)' /home/me/web/my.png /home/me/web/mynew.png

But when i use it with php:

<?php

error_reporting(E_ALL);
ini_set('display_errors', '1');

$output = shell_exec("convert -transparent 'RGB(249,249,255)' /home/me/web/my.png /home/me/web/mynew.png");

?>

i get the error:

convert: unable to open image `/home/me/web/mynew.png': @ error/blob.c/OpenBlob/2498.

Has anyone a idea?

is the path in the error message the correct path to your file? — John3136
– John3136, Commented Sep 5, 2012 at 9:02

pila · Accepted Answer · 2012-09-05 09:17:48Z

4

you have to use relative paths to your homedir (because of shell_exec) otherwise you have to use absolute paths.

But why dont you use imagemagick for php?

answered Sep 5, 2012 at 9:17

pila

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1 Comment

mcknight Over a year ago

Path is now corrected, but still the same error. I don't use imagemagick for php because I can't find the convert -transparent command in there...

heiglandreas · Accepted Answer · 2012-09-05 14:52:50Z

3

To me that looks like an access-rights issue. Your web server tries to write a file inside your home directory.

Normally your home-directory is protected in such a way that no one except yourself can write files in there. Therefore your web server can not create the new file while you can when using the terminal.

Check the access rights to the folder that shall contain the new image and allow the user that is running the web server to write to that folder.

answered Sep 5, 2012 at 14:52

heiglandreas

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