Script without jquery ui

Question

I have make a script for make columns the same height. This is my script:

function equalHeight(group) {
   tallest = 0;
   group.each(function() {
      thisHeight = $(this).outerHeight();
      if(thisHeight > tallest) {
         tallest = thisHeight;
      }
   });
   group.outerHeight(tallest);
};

equalHeight($(".list-links li"));

But i have a problem. In my website, i use jquery ui core. But i want delete that jquery ui. But if I remove the jquery ui. Then this script does not work anymore. Why?

Thanks for helping.

have you written this code in the ui core file by chance? :) — codeandcloud
– codeandcloud, Commented Sep 8, 2012 at 15:53

Alexander · Accepted Answer · 2012-09-08 16:20:29Z

2

jQuery's .outerHeight doesn't work as a setter method as you can see from the documentation. So, this line of code

group.outerHeight(tallest);

doesn't have any effect without jQuery UI.

jQuery UI wraps .inner* and .outer* methods and extend them with a setter method as you can see in the excerpt below from jquery.ui.core.js.

...
$.fn[ "outer" + name] = function( size, margin ) {
  if ( typeof size !== "number" ) {
    return orig[ "outer" + name ].call( this, size );
  }

  return this.each(function() {
    $( this).css( type, reduce( this, size, true, margin ) + "px" );
  });
};
...

These setters, for instance .outerHeight, sets the height of the element without the padding, border and optionally the margin.

edited Sep 8, 2012 at 16:20

answered Sep 8, 2012 at 16:04

Alexander

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Comments

dbf · Accepted Answer · 2012-09-08 15:51:27Z

0

The script snippet has, at least what I can tell, nothing to do with the UI core (widget interaction). I guess you are calling a UI core widget method somewhere, check error console, probably an undefined function or non-object as soon as you remove the UI core.

answered Sep 8, 2012 at 15:51

dbf

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