How to send a HTTP error for a Java RESTful web service?

Question

I have done this tutorial and now I want to throw an error from this webservice, like HTTP error code 403 or 400.

How can i do this? I noticed that i have an interface of type HttpServletResponse, but I don't know how I can use it. Do I have to import something else?

import java.util.Date;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.net.*;

import javax.servlet.http.HttpServletResponse;
import javax.ws.rs.Consumes;
import javax.ws.rs.PUT;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.QueryParam;
import javax.xml.ws.http.HTTPException;

import sun.awt.RequestFocusController;

import com.sun.jersey.spi.resource.Singleton;
import com.sun.research.ws.wadl.Request;
import com.sun.research.ws.wadl.Response;

Jozef Dropčo · Accepted Answer · 2012-09-10 14:11:14Z

4

You can do it like this.

@GET
public Response check(@QueryParam("username") String username) {
   if (facade.checkUser(username)) {
      return Response.status(Response.Status.NOT_FOUND).build();
   }
   return Response.ok().build();
}

answered Sep 10, 2012 at 14:11

Jozef Dropčo

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3 Comments

Sas Gabriel Over a year ago

and if i want to return a string or an int or one of this codes?

Jozef Dropčo Over a year ago

Set the entity of the response. Response.status(Response.Status.OK).entity("HELLO").build()

SysHex Over a year ago

Sorry about this, but I've downloaded the sources on the Tutorial link, been looking at this entry, and I cant figure what Response object you are using here. This import com.sun.research.ws.wadl.Response; doesn't have the status() method. Can you please help me here figure out what you two have seen that eluded me

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