Constructing a URL based on existing variables

Question

I'm a bit of a PHP newbie, and I'm trying to do what I believe is quite a complicated operation on a website. So I need your help :)

What I want to do is request a specific page for each client, the only URL variables involved are at the end, as normal.

Basically my variables have been set previously in the script, what I want to say is; The URL is http://site.com/index.php?image=$clientnumber Somehow.

if you guys could give me some insight on how to do this, that would be great!

Is your question about "constructing an URL" or about "how to generate a unique client number"? — nkr
– nkr, Commented Sep 12, 2012 at 9:46
are you setting those variables in the same (php-)script? or are they transfered via a form submit? because most likely you want to have a print_r() look in either $_POST or $_GET — Najzero
– Najzero, Commented Sep 12, 2012 at 9:47
It would be helpful to extend your question on what it is you exactly want as @nkr commented, that said, the relevant parts of the source code on what the situation is now, might be a good start to get some answers ;) — dbf
– dbf, Commented Sep 14, 2012 at 0:15

JvdBerg · Accepted Answer · 2012-09-12 09:46:39Z

1

You can use the sprintf function to do this:

$url = sprintf('http://site.com/index.php?image=%s', $clientnumber);

answered Sep 12, 2012 at 9:46

JvdBerg

21.8k8 gold badges40 silver badges55 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

alexbusu · Accepted Answer · 2012-09-12 09:47:08Z

1

PHP String Operators

$new_url = "http://site.com/index.php?image=$clientnumber";

or

$new_url = 'http://site.com/index.php?image=' . $clientnumber;

answered Sep 12, 2012 at 9:47

alexbusu

7914 silver badges14 bronze badges

1 Comment

JYuk Over a year ago

The variable is constant, it comes from a database earlier in the script, I basically need the URL to use in an image frame. It has authentication variables too, but I didn't want to complicate the question.

user399666 · Accepted Answer · 2012-09-12 09:48:39Z

0

$data = array('foo'=>'bar',
              'baz'=>'boom',
              'cow'=>'milk',
              'php'=>'hypertext processor');

echo http_build_query($data) . "\n";

Results in:

foo=bar&baz=boom&cow=milk&php=hypertext+processor

For your needs:

$data = array('image'=> $clientnumber);
echo 'index.php?' . $data;

Will give you:

index.php?image=878787283

answered Sep 12, 2012 at 9:48

user399666

20k7 gold badges49 silver badges68 bronze badges

1 Comment

JYuk Over a year ago

That seems like a more graceful solution. For the sake of simplicity I didn't say I was also adding $login and $pass to it. So an array would work significantly better, I think. Thanks!

Collectives™ on Stack Overflow

Constructing a URL based on existing variables

3 Answers 3

Comments

1 Comment

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

1 Comment

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related