PHP list multiple value into array

Question

I have a hotel database which has multiple rates due to the room types. I'd like to list it dynamically into array (of each room type) accordingly. My data structures are:

Hotel A : 1200-1500-1300-1700 //room type 1=1200usd/night, room type 2=1500usd/night ...
Hotel B : 1500-1200-1300
Hotel C : 800-850

And I'd like to list it into each room type. So I wrote:

while($rec = mysql_fetch_array($result_rate)) {  
    $_roomId = $rec['rid'];
    $_roomRate = $rec['rate'];

    list($ratez[]) = explode("-", $_rate); //because the room type is varied by hotel so I make it in array
}

So I expect the result should comes up like

echo "Room ID $_roomId=$ratez[$_roomId] USD ";

But the result is not as I expect. It keeps displaying error Fatal error: Unsupported operand types.

list does not work like that. Also, this code has 6 different variables all of which are used only once??? — Jon
– Jon, Commented Sep 15, 2012 at 11:43

Night2 · Accepted Answer · 2012-09-15 11:43:48Z

1

Use this:

$ratez[] = explode('-', $_rate);

Or this to save rates for each room:

$ratez[$_roomId] = explode('-', $_rate);

answered Sep 15, 2012 at 11:43

Night2

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2 Comments

Wilf Over a year ago

This is what I'm talking about @Night2. But still, I have an error : Fatal error: Unsupported operand types.

Night2 Over a year ago

Change your echo to this: echo 'Room ID '.$_roomId.'='.$ratez[$_roomId][0].' USD'; Inplace of [0] you can loop the array and use the right index.

Wilf · Accepted Answer · 2012-09-15 14:01:29Z

0

What I did is just:

$_rCostz=explode("-",$rec['cost']);

and echo the result in currency format as :

echo number_format($_rCostz[$room_id-1])

//because the room id starts with 1 but the array begins` with "0" so -1

Thank you very much, Night2 and others. Problem solved.

answered Sep 15, 2012 at 14:01

Wilf

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