regex in java with conditions

Question

I have to write Regex in Java according to the following conditions:

total digit character limit = 64
a single digit of 0 is acceptable
first digit must be 1 through 9 if more than one digit
following digits can be 0 through 9
two digits are allowed after a decimal point
comma's are not accepted

so far I have only got this:

(\\d{1,64})

Can someone help me

Tim Pietzcker · Accepted Answer · 2012-09-18 05:45:59Z

8

Pattern regex = Pattern.compile(
    "^             # Start of string                 \n" +
    "(?!.{65})     # Assert length not 65 or greater \n" +
    "(?:           # Match either                    \n" +
    " 0            #  0                              \n" +
    "|             # or                              \n" +
    " [1-9]\\d*    #  1-n, no leading zeroes         \n" +
    ")             # End of alternation              \n" +
    "(?:           # Match...                        \n" +
    " \\.          #  a dot                          \n" +
    " \\d{2}       #  followed by exactly 2 digits   \n" +
    ")?            # ...optionally                   \n" +
    "$             # End of string", 
    Pattern.COMMENTS);

answered Sep 18, 2012 at 5:45

Tim Pietzcker

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Comments

Mu Mind · Accepted Answer · 2012-09-18 05:57:22Z

1

Might be the most legible if you split it up into 4 scenarios:

(0(\.\d{1,2})?|[1-9](\d{0,63}|\d{0,61}\.\d|\d{0,60}\.\d\d))

That's a 0 optionally followed by a decimal and one or two more digits, or a 1-9 followed by one of:

up to 63 more digits
up to 61 more digits, a decimal, and one more digit
up to 60 more digits, a decimal, and two more digits

Definitely worth adding some comments inline with the Java regex, but I'm not too savvy with Java's regex syntax so I'll leave that as an exercise for the reader.

answered Sep 18, 2012 at 5:57

Mu Mind

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