Using Multiple Selectors in jQuery

Question

I have a working jQuery statement as follows

 var firstHeaderLineElement = $(".resultGridTable .tableColGroupAssociate");

I need to make this more generalized by making .tableColGroupAssociate as a variable. I have achieved this using following:

    var hideClass = '.tableColGroupAssociate';
    var firstHeaderLineElement = $(".resultGridTable").find(hideClass);

However, it requires a "find". Is there a better performing jQuery way for this?

Community · Accepted Answer · 2020-06-20 09:12:55Z

3

Using String concatenation:

var hideClass = '.tableColGroupAssociate';
var firstHeaderLineElement = $(".resultGridTable " + hideClass );

jQuery $(selector, context) format:

var hideClass = '.tableColGroupAssociate';
var firstHeaderLineElement = $(".resultGridTable", hideClass);

But internally it implements the .find().

Note

But jQuery always not implements the find() method. In modern browsers it try to implement the document.querySelectorAll() so that browser will try to parse it as a valid CSS selector.

If this default engine fails then jQuery parse the selector using its default engine Sizzle which using its internal mechanism for DOM traversing.

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Sep 18, 2012 at 5:54

thecodeparadox

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1 Comment

LCJ Over a year ago

Does String concatenation also use find() internally?

Tom · Accepted Answer · 2012-09-18 05:54:55Z

3

you can use multiple strings in selector identifying

var hideClass = '.tableColGroupAssociate';
var firstHeaderLineElement = $(".resultGridTable " + hideClass);

answered Sep 18, 2012 at 5:54

Tom

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