PHP preg_replace replacing line break

Question

When renumbering an array using

$arr=array_values($arr); // Renumber array

I realized that a line break is being introduced into one of the array strings, which I don't want.

My string is going from:

Property Type

to Property

Type

In any case I am using:

$newelement = preg_replace("/[^A-Za-z0-9\s\s+]/", " ", $element);

already to remove unwanted characters prior to database insertion, so I tried to change it to:

 $newelement = preg_replace("/[^A-Za-z0-9\s\s+'<br>''<br>''/n''/cr']/", " ", $element);

But there is no change, and the ?line feed/line break/carriage return is still there.

Am I doing the preg_replace call correctly?

line breaks are \n or \r or \r\n depending on the operating system. str_replace (array('\r\n', '\n', '\r'), ' ', $text) — Horen
– Horen, Commented Sep 19, 2012 at 15:54
You need to fix the underlying problem instead of trying to patch it up; array_values does not change the values, see this example: codepad.org/Mhbzjkl8 — jeroen
– jeroen, Commented Sep 19, 2012 at 16:14

Peter Mortensen · Accepted Answer · 2020-07-18 19:23:24Z

43

That preg looks a bit complicated. And then you have ^ in the beginning as not A-Z... or linefeed. So you don't want to replace linefeed?

How about

$newelement = preg_replace("/[\n\r]/", "", $element);

or

$newelement = preg_replace("/[^A-Za-z ]/", "", $element);

\s also matches linefeed (\n).

edited Jul 18, 2020 at 19:23

Peter Mortensen

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answered Sep 19, 2012 at 15:59

Antti Rytsölä

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1 Comment

Brian Wood Over a year ago

For the first alternative /\\[nr]/ would be a more exact pattern. Without those backslashes escaped it's going to replace the letters 'n' or 'r'.

Peter Mortensen · Accepted Answer · 2020-07-18 19:23:59Z

6

This should work too:

// char(32) is whitespace
// For CR
$element = strtr($element, chr(13), chr(32));

// For LF
$element = strtr($element, chr(10), chr(32));

edited Jul 18, 2020 at 19:23

Peter Mortensen

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answered Sep 19, 2012 at 16:09

Mahdi

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Comments

Peter Mortensen · Accepted Answer · 2020-07-18 19:24:15Z

4

This thing worked for me.

preg_replace("/\r\n\r\n|\r\r|\n\n/", "<br />", $element);

edited Jul 18, 2020 at 19:24

Peter Mortensen

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answered Oct 26, 2015 at 8:47

tashi

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Comments

Peter Mortensen · Accepted Answer · 2020-07-18 19:28:06Z

1

It's a hack, but you can do something like this:

    $email_body_string  = preg_replace("/\=\r\n$/", "", $email_body_string);

The replacement says find a line that ends with an equals sign and has the standard carriage return and line feed characters afterwards. Replace those characters with nothing ("") and the equals sign will disappear. The line below it will be pulled up to join the first line.

Now, this implies that you will never have a line that ends with an equals sign, which is a risk. If you want to do it one better, check the line length where the wrap (with the equals sign) appears. It's usually about 73 characters in from the beginning of the line. Then you could say:

    if (strlen(equals sign) == 73)
       $email_body_string  = preg_replace("/\=\r\n$/", "", $email_body_string);

edited Jul 18, 2020 at 19:28

Peter Mortensen

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answered Mar 9, 2016 at 16:39

Dave Strickler

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Comments

mickmackusa · Accepted Answer · 2024-03-12 07:15:59Z

0

Most simply, call preg_replace() on your flat array of values and use \v+ to target each occurrence each occurrence of one or more vertical whitespaces. (Demo)

$arr = [
    'Property Type',
    'Property

Type',
    'new
    
    
    
    
lines

again'
];

var_export(
    preg_replace('/\v+/', ' ', $arr)
);

Output:

array (
  0 => 'Property Type',
  1 => 'Property Type',
  2 => 'new lines again',
)

answered Mar 12, 2024 at 7:15

mickmackusa♦

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