Regex with a word boundary in python

Question

I am trying to captcha a particular string with a regex, however I am losing the first char.

The string is (06)12345678

My regex is

r'\b\((0[34679]{1})\)?([\- ]{0,1})[0-9]{3,4}([\- ]{0,1})[0-9]{3,5}'

but all I get in my match is

06)12345678

I really want that first ( also.

The ( and ) are conditional because sometimes there wont be (). but the word boundary are there to prevent numbers like

hello123456789

matching

regex = r'\b\(?(0[34679]{1})\)?([\- ]{0,1})[0-9]{3,4}([\- ]{0,1})[0-9]{3,5}'
matches = re.finditer(regex, '(06)12345678)')
for match in matches:
    print match.group(0)

any thoughts?

-- examples --

(06)12345678 should match, (06)12345678
06 12345678 should match, 06 12345678
1234567890 should match, 1234567890
=12345678 no match

cottontail · Accepted Answer · 2023-05-02 18:49:43Z

2

Try escape second "(", not first one, and the last but one ")" before first ?.

Live demo: https://regex101.com/r/5h3FBr/1

edited May 2, 2023 at 18:49

cottontail

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answered Sep 20, 2012 at 12:51

AbstractProblemFactory

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3 Comments

Wizzard Over a year ago

Not quite, it didn't work I just ended up with 12345678 it didn't include the (06) at the start.

Wizzard Over a year ago

Thanks for the refiddle, however if you change it from (06) to, 12345678 then it doesn't match. The () are optional. Hence the /(? on each one. Examples added to the question.

Wizzard Over a year ago

Nearly there, the last one shouldn't match, which is where the whole word boundary came into it (see OP). So =12345678 should not match

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