PHP function json_decode decodes float value with zeros after point as int

Question

I have a JSON string that contains some key with the following value: 123.00. When I use json_decode function I get the decoded string where the previous key equal to 123, not to 123.00. Is there a way to correct decode such values without wrapping into quotes?

Daniel Li · Accepted Answer · 2012-09-21 13:51:22Z

7

This is currently being brought up as a PHP bug:

Bug Report: https://bugs.php.net/bug.php?id=50224

In the future, there may be functionality to pass a flag through the options parameter for stricter typing. For now, however, wrapping it in quotes will have to suffice.

answered Sep 21, 2012 at 13:51

Daniel Li

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3 Comments

Ihor Timoshenko Over a year ago

Thank you for your response and for the link!

Sverrir Sigmundarson Over a year ago

Fixed as of PHP 7.0, new option available for json_decode, JSON_PRESERVE_FRACTIONAL_PART

Bjørn Lindner Over a year ago

I believe it should be JSON_PRESERVE_ZERO_FRACTION. See respective commit

Zevi Sternlicht · Accepted Answer · 2012-09-21 13:52:23Z

1

I do not think it is possible!

answered Sep 21, 2012 at 13:52

Zevi Sternlicht

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Comments

TheMonkeyKing · Accepted Answer · 2012-09-21 14:39:32Z

1

//convert the json to a string before json_decode
$res = preg_replace( '/next_cursor":(\d+)/', 'next_cursor":"\1"', $json );

edited Sep 21, 2012 at 14:39

answered Sep 21, 2012 at 14:15

TheMonkeyKing

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Chris · Accepted Answer · 2012-09-21 13:51:38Z

0

number_format($number, 2)

output the number through that?

answered Sep 21, 2012 at 13:51

Chris

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Comments

andyrandy · Accepted Answer · 2014-11-28 13:05:00Z

0

You can use the JSON_BIGINT_AS_STRING option, for example:

$json = json_decode($input, true, 512, JSON_BIGINT_AS_STRING);

Careful though, this only works with PHP 5.4+!

edited Nov 28, 2014 at 13:05

answered Nov 28, 2014 at 12:59

andyrandy

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