Return a value via a gdb user-defined command

Question

I'm debugging with a core-file, so I have no active process in which to run anything.

I'm using gdb user-defined commands to inspect a bunch of data from the core file, and attempting to simplify the process using user-defined commands.

However, I cannot find a way to make the user-defined commands return values which could be used in other commands.

For example:
(note the comment on the "return" line)

define dump_linked_list
    set $node = global_list->head
    set $count = 1
    while $node != 0
        printf "%p -->", $node
        set $node = $node->next
        set $count = $count + 1
    end
    return $count  ## GDB doesn't understand this return
end

Ideally, my dump_linked_list command would return the number of nodes found in the list, so that it could be used in another defined command:

define higher_function
    set $total_nodes = dump_linked_list
    printf "Total Nodes is %d\n", $total_nodes
end

Is such a thing possible in gdb commands?

I feel it must be, but I've been searching documentation and cannot find a mention of it, or any examples.

CanadiaDan · Accepted Answer · 2013-02-07 10:04:57Z

6

I found out gdb seems to pass by name which can be used to pass back a return value. A little more flexible that just using a single global variable.

(gdb) define foo
Type commands for definition of "foo".
End with a line saying just "end".
>set $arg0 = 1
>end
(gdb) set $retval = 0
(gdb) p $retval
$3 = 0
(gdb) foo $retval
(gdb) p $retval
$4 = 1

answered Feb 7, 2013 at 10:04

CanadiaDan

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Comments

sirgeorge · Accepted Answer · 2012-09-24 20:56:40Z

1

As far as I know GDB does not have such a functionality. You can set a variable of some name that you know and use it as a "return" value. For example always set the variable retval like this:

set $retval = <whatever value>

Then all your newly defined functions can use it as a return value from previously called functions. I know this is only workaround, but it is relatively simple and it works.

answered Sep 24, 2012 at 20:56

sirgeorge

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