Javascript Replace via RegEx

Question

I am trying to replace 3 chars with 3 other chars to build/mask an email address for a form.

This works only once or on the first instance of finding it:

email = "email1#domain!com|email2#domain!com|email3#domain!com";
email.replace("#","@").replace("!",".").replace("|",",");

The above code resulted in: [email protected],email2#domain!com|email3#domain!com

After some reading I read about using RegEx which is the portion of coding I can never wrap my head around:

email.replace("/#/g","@").replace("/!/g",".").replace("/|/g",",");

That didn't work either and left it the same as the original var.

What am I doing wrong?

Niet the Dark Absol · Accepted Answer · 2012-09-25 22:29:11Z

4

Do not put quotes around the regex. Regexes are literals that use / as a boundary.

Additionally, you will need to escape the | because it has a special meaning.

Finally, .replace is not transformative. It returns the result.

email = email.replace(/#/g,'@').replace(/!/g,'.').replace(/\|/g,',');

answered Sep 25, 2012 at 22:29

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1 Comment

Thanks - will accept this answer when I can in a few minutes!

Bergi · Accepted Answer · 2012-09-25 22:28:49Z

1

Using regex literals, you omit the quotes (and you'll need to escape the pipe):

email.replace(/#/g,"@").replace(/!/g,".").replace(/\|/g,",");

answered Sep 25, 2012 at 22:28

Bergi

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Timo Kähkönen · Accepted Answer · 2012-09-25 22:34:10Z

0

email = "email1#domain!com|email2#domain!com|email3#domain!com";
email=email.replace(/#/g,"@").replace(/!/g,".").replace(/\|/g,",");

answered Sep 25, 2012 at 22:34

Timo Kähkönen

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