Format HTML page according to PHP array

Question

I have an unsorted and dynamically changing array in php where I have values stored as in "blue", "red", "green". The rest of the array consists of strings like "wet", "dry", "humid". Now I want to print respective titles before printing the strings to my html page. How can I achieve this?

Above code produces problems since if else fires, before all three colors have been echoed out, it will print the heading again.

Edit:

Array: blue, humid, green, wet, dry, red.

echo "<h3>Color</h3><br>";
foreach($array as $value){
if ($value == "blue" || $value == "red" || $value == "green") {
    echo $value;
}
echo "<h3>Weather</h3><br>";
foreach($array as $value){
if ($value != "blue" || $value != "red" || $value != "green") {
    echo $value;
}

It would really help if you'd provide us with your array structure. — Havelock
– Havelock, Commented Sep 27, 2012 at 13:15

Havelock · Accepted Answer · 2012-09-27 13:04:04Z

1

Yes, because your boolean expression isn't correct. It should be

if($file == 'blue' || $file == 'red' || $file == 'green')

The way you've written it it will be equal to

if($file == 'blue' || true || true)

And with the logical OR the expression is TRUE if only one of the variables equals TRUE.
Edit
On a second reading, echo the heading before the foreach loop.

answered Sep 27, 2012 at 13:04

Havelock

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3 Comments

Cloudscape Germany Over a year ago

yea I know about the boolean expression, sorry for that, it is not the issue here. The point is that the script WORKS FINE - but the if the array is UNSORTED, it does produce the heading more than once. I need to sort the thing before hand and split it into 2 different arrays I guess.

PenguinCoder Over a year ago

@StephanKristyn With the code you have shown, this certainly is an issue. As for the rest of your code; how are we to know?? You didn't show it.

Cloudscape Germany Over a year ago

Echoing the (colors) heading before the foreach won't help either, in case the array is unsorted, think about it. Item's will get left out and then get printed without (colors) heading after the second (weather) heading was printed in the else condition.

Teena Thomas · Accepted Answer · 2012-09-27 13:03:55Z

0

if statement syntax is wrong. It needs to be if ($file == "blue" || $file == "red" || $file == "green") {

echo the heading echo "<h1>Colours</h1>"; before the foreach loop, like this:

       echo "<h1>Colours</h1>";      
       foreach($file_list as $file) {

      if ($file == "blue" || "red" || "green") {        
         echo $file;
        }
      else { ...}

answered Sep 27, 2012 at 13:03

Teena Thomas

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2 Comments

Cloudscape Germany Over a year ago

<h2>Weahter</h2> prints in else condition, but if green hasn't been echoed yet, you will have a problem.

Teena Thomas Over a year ago

you would need to show the entire code(atleast the if-else statement), for us to figure out your question. Also, the structure for $file_list

Cloudscape Germany · Accepted Answer · 2012-09-27 13:27:31Z

0

I got it myself. Changing the logical ORs in the second foreach loop does print out only the weather conditions as expected.

echo "<h3>Color</h3><br>";
foreach($array as $value){
if ($value == "blue" || $value == "red" || $value == "green") {
    echo $value;
}
echo "<h3>Weather</h3><br>";
foreach($array as $value){
if ($value != "blue" && $value != "red" && $value != "green") {
    echo $value;
}

answered Sep 27, 2012 at 13:27

Cloudscape Germany

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1 Comment

Havelock Over a year ago

well done, now you can mark it as an answer - nothing wrong with that ;-)

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