How to write an exception catching code works in Python2.4 to Python3

Question

Is there anyway to write an exception catch code that's compatible from python 2.4 to python 3?

Like this code:

# only works in python 2.4 to 2.7
try:
    pass
except Exception,e:
   print(e)

# only works in python 2.6 to 3.3
try:
    pass
except Exception as e:
    print(e)

A lot of projects maintain their code for python 2, and use 2to3 to automatically convert it to python 3 as necessary. That is usually easier than trying to write code that is compatible with both (this probably won't be the most difficult issue you come across). — James
– James, Commented Oct 1, 2012 at 23:51

nneonneo · Accepted Answer · 2012-10-01 23:36:27Z

17

Trying to write code that works in both Python 2 and Python 3 is ultimately rather futile, because of the sheer number of differences between them. Indeed, a lot of projects are now maintained in separate Python 2 and Python 3 versions as a result.

That said, if you're hell-bent on doing this in a super-portable way...

import sys
try:
    ...
except Exception:
    t, e = sys.exc_info()[:2]
    print(e)

answered Oct 1, 2012 at 23:36

nneonneo

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3 Comments

yegle Over a year ago

Thank you nneonneo for your answer, and thank you @gnibbler for your tip :-)

nneonneo Over a year ago

@gnibbler: I believe it is..."The information returned is specific both to the current thread and to the current stack frame."

Alex Dupuy Over a year ago

If you're using Logger classes (and really, you should be), you don't even need to import sys and use inscrutable code to print your exceptions - you can just call Logger.exception("message") or the class method logging.exception("message") and the exception message and/or stack trace will be included in the logger output.

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