Regex pattern issue

Question

I have the following string:

!date +10 (yyyy-MM-dd'T'HH:mm:ssz)

this string could be also (notice the minus instead of the plus.:

!date -10 (yyyy-MM-dd'T'HH:mm:ssz)

I need a regex pattern that will extract the numeric digits after the + (or -). There could be more than one digit.

I also need a pattern to extract the contents of the brackets ();

I've had a play around on regex pal. but couldn't get a working pattern.

Cheers.

What you have tried ?What should be your output?

thar45
– thar45

2012-10-04 09:42:53 +00:00
Commented Oct 4, 2012 at 9:42 — thar45
– thar45, Commented Oct 4, 2012 at 9:42

Reimeus · Accepted Answer · 2012-10-04 09:50:12Z

3

To pick out the number & bracket content, you could do:

String str = "date +10 (yyyy-MM-dd'T'HH:mm:ssz)";
Matcher m = Pattern.compile(".*[+|-](\\d+).*\\((.*)\\).*").matcher(str);
if (m.matches()) {
    System.out.println(m.group(1));
    System.out.println(m.group(2));
}

answered Oct 4, 2012 at 9:50

Reimeus

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skunkfrukt · Accepted Answer · 2012-10-04 09:46:04Z

0

This regex should give you a match with the digits after the +/- and the contents of the parentheses in the first and second capturing group, respectively:

"!date\\s[+-](\\d+)\\s\\(([^)]*)\\)"

answered Oct 4, 2012 at 9:46

skunkfrukt

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halex · Accepted Answer · 2012-10-04 09:49:34Z

0

The following regex leads to 2 capturing groups with the contents you want

"!date\\s[+-](\\d+)\\s\\((\\d{4}-\\d{2}-\\d{2}'T'\\d{2}:\\d{2}:\\d{2}z)\\)"

answered Oct 4, 2012 at 9:49

halex

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