Can't read int from input file in java

Question

I've got a program that reads an input file with 4000 1's or 0's, one on each line.

The program compiles fine but when it runs I get the following error:

ˇ˛0Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Scanner.java:840)
at java.util.Scanner.next(Scanner.java:1461)
at java.util.Scanner.nextInt(Scanner.java:2091)
at java.util.Scanner.nextInt(Scanner.java:2050)
at Project1.main(Project1.java:27)

For some reason when I look at the text file, the first line is a 0 and nothing else yet when the program reads the first line it gets ˇ˛0. I also tried using a buffered reader with no luck. Could anyone please offer some input. Thank you!

Here's my code:

import java.io.*;
import java.util.Random;
import java.util.Scanner;

public class Project1 {

    public static void main(String[] args) {
        int [] stream = new int[4000];
        int [] received = new int[4000];
        int corrupt = 0;
        float standardDev = 0;
        float [] averages = new float[4000];
        float averagev = 0;
        float voltage = 0;
        try {
            Scanner st = new Scanner(new File("CS 380 bit feed.txt"));
            System.out.print(st.next());
            FileWriter outFile = new FileWriter("output");
            PrintWriter out = new PrintWriter(outFile);
            int i=0;
            Random rand = new Random();

            stream[i]=st.nextInt();
            if (stream[i] == 0)
                voltage = (float) (2.49 * rand.nextFloat());
            else
                voltage = (float) ((2.5 * rand.nextFloat()) + 2.5);
            if (voltage < 2.5)
                received[i] = 0;
            else
                received[i] = 1;
            averagev = voltage;
            averages[i] = voltage;
            if (stream[i] != received[i])
                corrupt++;
            i++;

            while (i < 4000) {
                stream[i]=st.nextInt();
                if (stream[i] == 0)
                    voltage = (float) 2.49 * rand.nextFloat();
                else
                    voltage = (float) ((2.5 * rand.nextFloat()) + 2.5);
                averagev = ((averagev * i) + voltage)/(i+1);
                if (voltage <= averagev)
                    received[i] = 0;
                else
                    received[i] = 1;
                if (stream[i] != received[i])
                    corrupt++;
                i++;
            }
            averagev = 0;
            int j = 0;
            while (j < 4000) {
                for (int k = 0; k<8; k++) {
                    out.print(received[j]);
                    averagev = averages[i] + averagev;
                    j++;
                }
                out.println("    " + averages[j]);
            }

        }
        catch (FileNotFoundException e) {
              e.printStackTrace();
        } 
        catch (IOException e) {
              e.printStackTrace();
        }
        averagev = averagev / 4000;
        for (int k = 0; k<4000; k++) 
            standardDev = ((averagev - averages[k])*(averagev - averages[k])) + standardDev;
        standardDev = standardDev/4000;

        System.out.println("Errors: " + corrupt);
        System.out.println("Percentage Corrupt: " + corrupt / 4000);
        System.out.println("Average of Average Voltages: " + averagev);
        System.out.println("Standard Deviation: " + standardDev);        
    }
}

Perhaps your file is corrupt or contains BOM en.wikipedia.org/wiki/Byte_order_mark characters. I suggest creating a new file with just 0. BTW Your voltages cannot be between 2.49 and 2.50. e.g. 2.491 Is that intended? — Peter Lawrey
– Peter Lawrey, Commented Oct 9, 2012 at 9:23

artbristol · Accepted Answer · 2012-10-09 09:22:17Z

2

Look at the file in a hex editor. It might be corrupt or have a Byte Order Mark at the beginning, which wouldn't necessarily show up in a text editor.

answered Oct 9, 2012 at 9:22

artbristol

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