Recognise pattern from a string using php

Question

let's say i have a string like this:

$string = 'Lorem Ipsum available, <a href="##article-6##">but the majority</a> have suffered alteration in some form, by injected humour.';

Notice the <a href="##article-6##">but the majority</a>

Using this i want to link my articles based on their id's from the database.

Now, how can a perform a preg_replace on that string to see if i have something like ##article-6## and extract only that number?

Is this idea a good one? Can i do it in a better way?

EDIT:

I did it like this:

$post_content = preg_replace_callback('/##article-(\d+)##/', function($matches){$args = explode(',', $matches[1]); // separate the arguments
return call_user_func_array('article_seo_url', $args); /* pass the arguments to article_seo_url function*/ }, $post_content);

Using this code i can also replace multiple url's

I want to do that to be sure i always have the link to the correct url in case i change the structure of the url's. — m3tsys
– m3tsys, Commented Oct 14, 2012 at 21:10

h2ooooooo · Accepted Answer · 2012-10-14 21:14:28Z

1

If you want to do a preg_replace, you'd want to use a regex such as /##article-(\d+)##/ and do something like this:

$string = 'Lorem Ipsum available, <a href="##article-6##">but the majority</a> have suffered alteration in some form, by injected humour.';
$string = preg_replace('/##article-(\d+)##/', 'link/to/article/with/id/$1.html', $string);

would result in $string being:

Lorem Ipsum available, <a href="link/to/article/with/id/6.html">but the majority</a> have suffered alteration in some form, by injected humour.

answered Oct 14, 2012 at 21:14

h2ooooooo

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2 Comments

m3tsys Over a year ago

yes. that outputs what you've said but if i use $string = preg_replace('/##article-(\d+)##/', article_seo_url($1), $string); it doesn't work. I get this error: Parse error: syntax error, unexpected T_LNUMBER, expecting T_VARIABLE or '$' in...

m3tsys Over a year ago

even i didn't used exactly your code i accepted your answer because it is the most similar with the final code i used.

user1726343 · Accepted Answer · 2012-10-14 21:04:48Z

0

If your href is stored in a variable like so:

$href="http://www.domain.com";

You can just insert that directly into the string, like so:

$string = "Lorem Ipsum available, <a href=\"$href\">but the majority</a> have suffered alteration in some form, by injected humour.";

Please note that it is important you either escape your literal quotes or use a different kind, in this case singles.

answered Oct 14, 2012 at 21:04

user1726343

2 Comments

m3tsys Over a year ago

No, that string is extracted from the database. In that way i want to link another articles based on their id. I want to do that to be sure i always have the link to the correct url in case i change the structure of the url's. I thought is a good idea to do that.

user1726343 Over a year ago

In that case, please try Rick Calder's solution

Rick Calder · Accepted Answer · 2012-10-14 21:29:18Z

0

If the ID is always 3 digits you don't even need regex.

$string = 'Lorem Ipsum available, <a href="##article-6##">but the majority</a> have suffered alteration in some form, by injected humour.';
$start = strpos($string, 'article-');
$articleId = substr ( $string , intval($start)+8 , 3 );

edited Oct 14, 2012 at 21:29

answered Oct 14, 2012 at 21:02

Rick Calder

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4 Comments

Rick Calder Over a year ago

Yeah, copying and pasting is bad. Sorry about that.

m3tsys Over a year ago

first you forgot ;. second: this code shows me a error: Fatal error: Call to undefined function int() in...

Rick Calder Over a year ago

Fixed, sorry I don't use those functions often, was off the top of my head.

Rick Calder Over a year ago

... okay do the math then. I told you I don't use these functions often. instead of +1 make it +8

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