json generating array problems

Question

I want to generate a json array and store it in my db. I get the values and run a loop to generate.

when I encode it I'm getting ArrayArrayArray

Can anyone see where I'm going wrong

for ($i=0; $i<=$sTotal;$i++){ 
    $layout_array .= array(array("cellID" => '"'. $_POST['cell_'.$i] .'"',"studentID" => $_POST['user_'.$i]),);
}
$layout_array .= array(array("cellID" => "null","studentID" => "null"));
$layout = json_encode($layout_array);
echo $layout;

Cheers

why are you concatenating $layout_array?

dnagirl
– dnagirl

2012-10-15 14:11:21 +00:00
Commented Oct 15, 2012 at 14:11 — dnagirl
– dnagirl, Commented Oct 15, 2012 at 14:11

Ofir Baruch · Accepted Answer · 2012-10-15 14:20:18Z

2

The problem is that your $layout_array is a String , because you're using .= (concatenating).

Instead of:

$layout_array .= array(array("cellID" => '"'. $_POST['ce...

Do:

$layout_array[] = array(array("cellID" => '"'. $_POST['ce....

And change the next line as well:

$layout_array .= array(array("cellID" => "null","studentID" => "null"));

BTW , why not using serialize and unserialize instead of json encoding?

EDIT: For your comfort , links to the php manual of the functions I've suggested.

http://php.net/manual/en/function.serialize.php

http://php.net/manual/en/function.unserialize.php

edited Oct 15, 2012 at 14:20

answered Oct 15, 2012 at 14:12

Ofir Baruch

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Comments

Matt Humphrey · Accepted Answer · 2012-10-15 14:19:09Z

0

You should be using += to join your arrays, not ..

Edit: Ignore this and see comments. This will add elements to the current scope of the array, you should be using $array[] = array(..) as the other answer states.

edited Oct 15, 2012 at 14:19

answered Oct 15, 2012 at 14:12

Matt Humphrey

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3 Comments

Matt Humphrey Over a year ago

I'm fully aware it's PHP! You use .= with strings, += with numbers and arrays.

dnagirl Over a year ago

@sircapsalot: .= is for concatenating. += is for adding. Both are valid PHP operators. But I don't think I've ever seen either used for adding new elements to an array.

Matt Humphrey Over a year ago

To be honest this answer will not as expected. It's fully valid PHP but to add a new element to an array it will not work. I was thinking of the array() + array() syntax.

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