Using IF Statement in a Batch Script

Question

I'm new to Batch Programming.I'm trying to use an IF Condition in one of my Batch Script.The Code looks like this.

:rmfile
:: removes the file based on it's age.
::                     
SETLOCAL
set file=%~1
set age=%~2
set thrshld_days=40
if %age% LSS 40 
echo.%file% is %age% days old 
EXIT /b

Now the Problem is that even if the age of a file is more than 40 i'm getting the file printed.which actually should not happen.

Please Help me in this regard..Thanks!

Christian Hayter · Accepted Answer · 2012-10-16 07:06:21Z

1

Either put it on one line:

if %age% LSS 40 echo.%file% is %age% days old

or use block delimiters:

if %age% LSS 40 (
    echo.%file% is %age% days old
)

answered Oct 16, 2012 at 7:06

Christian Hayter

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Comments

wmz · Accepted Answer · 2012-10-16 07:07:37Z

1

if %age% LSS 40 
echo.%file% is %age% days old

is interpreted as conditional expression with empty body (first line) and unconditional echo (second line). You need to either put them on one line:

if %age% LSS 40 echo.%file% is %age% days old

or use parens to create block (but the opening bracket must be on the same line as if):

if %age% LSS 40 (
   echo.%file% is %age% days old
)

answered Oct 16, 2012 at 7:07

wmz

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1 Comment

user1749169 Over a year ago

I tried with Parens as suggested but no luck :( Echo statement is getting printed for every file..

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