Java String.split not working

Question

I have a string in following format:

CT-d0712728-867d-4cc4-bd0c-b2a679b8385f~#$~2012-10-16 02:13:27 PM

Can I use String.split("~#$~") or do I have to use StringTokenizer? I will have ONLY 2 parameters in above string, that's why I was trying to use String.Split("~#$~") but it doesn't seem to work.

What happened when you tried it? Did you capture the results into a String[]? — Makoto
– Makoto, Commented Oct 16, 2012 at 18:35

Pshemo · Accepted Answer · 2014-08-14 16:58:56Z

7

$ is special character in regex (it means "end of a line"). To make it simple literal you need to escape it, for example with

"\\$",
"[$]"
or using quotations "\\Q$\\E".

edited Aug 14, 2014 at 16:58

answered Oct 16, 2012 at 18:36

Pshemo

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Rohit Jain · Accepted Answer · 2012-10-16 18:36:24Z

1

Since split() method takes the paremeters as Regex, and $ is special meta-character in Regex. You need to escape the $ sign: -

    System.out.println(str.split("~#\\$~")[0]);
    System.out.println(str.split("~#\\$~")[1]);

answered Oct 16, 2012 at 18:36

Rohit Jain

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banjara · Accepted Answer · 2012-10-16 18:36:37Z

0

try

String s = "CT-d0712728-867d-4cc4-bd0c-b2a679b8385f~#$~2012-10-16 02:13:27 PM";

Arrays.toString(s.split("~#\\$~"))

answered Oct 16, 2012 at 18:36

banjara

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Tom G · Accepted Answer · 2012-10-16 18:36:52Z

0

String str = "CT-d0712728-867d-4cc4-bd0c-b2a679b8385f~#$~2012-10-16 02:13:27 PM";
String[] pieces = str.split("~#\\$~");

answered Oct 16, 2012 at 18:36

Tom G

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Sreedhar · Accepted Answer · 2012-10-16 18:59:48Z

0

you can do this using String.split(). No need to use StringTokenizer. See then below example.

String s="CT-d0712728-867d-4cc4-bd0c-b2a679b8385f~#$~2012-10-16 02:13:27 PM";
        String test[]=s.split("\\~\\#\\$\\~");
        System.out.println(test[0]);
        System.out.println(test[1]);

Let me know i you have any questions.

answered Oct 16, 2012 at 18:59

Sreedhar

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