PHP: Call function inside preg_replace

Question

The below code responsible for bbcode tags in dle script. "\1" is the link which i would like to call with function, but instead I'm getting plain text

        $txt = preg_replace( "#<!--dle_video_begin:(.+?)-->(.+?)<!--dle_video_end-->#is", '[video=\\1]', $txt );

my function

function videoD ($str) {
        if (strpos($str,'http://') !== false) {
                $vid = uppod_encode($str);
                echo (uppod_encode($str));

        } else {
                $vid = uppod_decode($str);
                echo (uppod_encode($vid));
        }
}

what i've tried:

$txt = preg_replace( "#<!--dle_video_begin:(.+?)-->(.+?)<!--dle_video_end-->#is", '[video=videoD(\\1)]', $txt );


$txt = preg_replace( "#<!--dle_video_begin:(.+?)-->(.+?)<!--dle_video_end-->#is", '[video=videoD(1)]', $txt );

$txt = preg_replace( "#<!--dle_video_begin:(.+?)-->(.+?)<!--dle_video_end-->#is", '[video=\\videoD(1)]', $txt );

@cbuckley - preg_replace_callback, yes. But the e modifier should be avoided. — Spudley
– Spudley, Commented Oct 20, 2012 at 14:16
@Spudley couldn't agree more; not sure why I even suggested it ;-) — cmbuckley
– cmbuckley, Commented Oct 20, 2012 at 14:19

CodeAngry · Accepted Answer · 2012-10-20 14:18:23Z

2

$txt = preg_replace_callback('#<!--dle_video_begin:(.+?)-->(.+?)<!--dle_video_end-->#is', function($matches){
    return "[video=videoD({$matches[1]})]";
}, $txt);

answered Oct 20, 2012 at 14:18

CodeAngry

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2 Comments

Crazy_Bash Over a year ago

i'm getting the output of: [video=videoD(link)]

CodeAngry Over a year ago

@Crazy_Bash I'm using the first capture group like in your examples. Use $matches[2] if you need the second one. Or var_dump($matches) in the callback to see how it looks and pick the one you need.

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