split string in xsl and update attribute

Question

I have a xml file with below structure

    <project>
    <dependency id="abc" version="1.2.3.4"/>
    </project>

I need to read this xml and update another xml with the value of id and version. Earlier i did this with an xsl like below, which was working fine:

    <xsl:attribute name="id">
    <xsl:value-of select="@id"/>
    </xsl:attribute>

    <xsl:attribute name="version">
    <xsl:value-of select="@version"/>
    </xsl:attribute>

Now I need to set the attribute value of version as [1.2,1.3), how can I do this? I tried something like this below, but I dont think I'm getting no where.

    <xsl:variable name="MinVersion"/>
    <xsl:variable name="MaxVersion"/>

<xsl:for-each select="tokenize(@version,'.')">

<xsl:if test="(position( )) = 2">
    <xsl:value-of select="concat($MinVersion,.)"/>
</xsl:if>
<xsl:otherwise>
    <xsl:value-of select="concat($MinVersion,.,'.')"/>
</xsl:otherwise>

<xsl:if test="(position( )) = 2">
    <xsl:value-of select="concat($MaxVersion,number(.)+1)"/>
</xsl:if>
<xsl:otherwise>
    <xsl:value-of select="concat($MaxVersion,.,'.')"/>
</xsl:otherwise>
 </xsl:for-each>

How can I do this?

UPDATE: I tried to debug this in Visual Studio and got error message stating tokenize is not a recognized function. After some searching found .NET framework supports only XSLT 1.0 processor. Any solution with 1.0 would be helpful.

Should your output be like follows: [$MinVersion - Firstnumber.Secondnumber] [$MaxVersion- Firstnumber.Thirdnumber] ? should it always follow this pattern ? — Madurika Welivita
– Madurika Welivita, Commented Oct 22, 2012 at 14:50
Microsoft's XSLT processors in the .NET framework (i.e. XslCompiledTransform and XslTransform) are XSLT 1.0 processors but there are third party XSLT 2.0 processors like the .NET version of Saxon 9 saxon.sourceforge.net/#F9.4HE or AltovaXML (usable in .NET via COM interop) or XmlPrime. So that way you can use the tokenize function in XSLT with .NET. — Martin Honnen
– Martin Honnen, Commented Oct 22, 2012 at 15:53

Madurika Welivita · Accepted Answer · 2012-10-23 08:45:04Z

2

Try following, Hope it will solve your problem.(I have Changed my prevous answer, check following new one.)

<xsl:variable name="testVersion" select="@version"></xsl:variable>
<xsl:variable name="separator" select="'.'"></xsl:variable>


<xsl:if test="string-length($testVersion) > 0">

  <xsl:variable name="firstnumber"     select="substring-before($testVersion, $separator)"/>
  <xsl:variable name="after-separator" select="substring-after($testVersion, $separator)"/>       
  <xsl:variable name="secondnumber"    select="substring-before($after-separator, $separator)"/>        

  <xsl:variable name="outputvalue">
    <xsl:text>[</xsl:text>
    <xsl:value-of select="$firstnumber"></xsl:value-of>
    <xsl:text>.</xsl:text>
    <xsl:value-of select="$secondnumber"></xsl:value-of>
    <xsl:text>,</xsl:text>
    <xsl:value-of select="$firstnumber"></xsl:value-of>
    <xsl:text>.</xsl:text>
    <xsl:value-of select="number($secondnumber)+1"></xsl:value-of>
    <xsl:text>)</xsl:text>
  </xsl:variable>

  <xsl:value-of select="$outputvalue"/>
</xsl:if>

edited Oct 23, 2012 at 8:45

answered Oct 22, 2012 at 15:22

Madurika Welivita

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4 Comments

Karun Over a year ago

Madurika: The output should always be in the following pattern, assuming @version is 1.1.234.5678 I need a value in a variable like below: [firstnumber.secondnumber, firstnumber,secondnumber+1) I'll check the substring option, if the firstnumber is 2 digit number, I guess the proposed solution might fail. Let me check it out though Martin: Saxon is not an feasible option right now, because this will be called inside an MSBuild script.

Sean B. Durkin Over a year ago

@KarunakaranPannirSelvam There is no problem calling Saxon from within an MSBuild script. You can use the console version of Saxon.

Madurika Welivita Over a year ago

@Karun please be kind enough to up vote for the answer by clicking up arrow head. .... cheers....!!!!!

Karun Over a year ago

I tried to up vote, looks like I need more reputation to do that.

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