AJAX/Javascript function not working

Question

Hi I am using an ajax call to a function called build_Array. This function should break up myString which is "Call 1-877-968-7762 to initiate your leave.,1,0,through;You are eligible to receive 50% pay.,1,365,through;Your leave will be unpaid.,1,0,After;" into sections divided by the commas into a 2d array. But it is not working. It says all of the values for the array are undefined. Here is where I call the function inside the ajax... (It works in the jsfiddle http://jsfiddle.net/ChaZz/3/)

var request = new XMLHttpRequest();
  request.onreadystatechange = function() {
    if (request.readyState == 4 && request.status == 200) {
      var myString = request.responseText;
      myString = build_Array(myString);
      document.getElementById('ajax').innerHTML = myString;
    }
  }

And here is the function build_Array...

function build_Array (myString) {
  var mySplitResult = myString.split(';');
  var myArray = new Array(mySplitResult.length);

  //may need to get rid of -1
  for(var i = 0; i < mySplitResult.length -1; i++){
    myArray[i] = new Array(4);
    var mySplitResult2 = mySplitResult[i].split(',');

    for(var z = 0; z < mySplitResult2.length; z++) {
        myArray[i][z] = mySplitResult2[z];
    }
  }
  var final_message = myArray[1][1];
  return final_message;
}

Shmiddty · Accepted Answer · 2012-10-26 20:34:39Z

2

http://jsfiddle.net/ChaZz/5/

var myString = "Call 1-877-968-7762 to initiate your leave.,-30,0,through;You are eligible to receive 50% pay.,0,365,through;Your leave will be unpaid.,365,0,After;";

function build_Array (myString) {
  var mySplitResult = myString.split(';');
  var myArray = [];

  for(var i = 0; i < mySplitResult.length; i++){
    myArray[i] = [];
    var mySplitResult2 = mySplitResult[i].split(',');

    for(var z = 0; z < mySplitResult2.length; z++) {
        myArray[i][z] = mySplitResult2[z];
    }
  }
  var final_message = myArray[1][1];
  return final_message;
}

console.log(build_Array(myString)); // 0

answered Oct 26, 2012 at 20:34

Shmiddty

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2 Comments

John Doe Over a year ago

what does the console.log do?

Shmiddty Over a year ago

The developer console that is in every modern browser.

Barmar · Accepted Answer · 2012-10-26 22:28:23Z

0

There's no need for the loop to copy from mySplitArray2 to myArray, just assign the array returned by split directly to that element of the new array. And array.push can be used to build up an array incrementally.

function build_Array (myString) {
  var myArray = [];
  for (substring in myString.split(';')){
    myArray.push(substring.split(','));
  }
  var final_message = myArray[1][1];
  return final_message;
}

answered Oct 26, 2012 at 22:28

Barmar

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