char name[50];
int valid;
do{
valid=1;
printf("Enter name for Salesman: ");
fgets(name,50,stdin);
if(!isalpha(*name)) //it will only scan for the first character of string
{
printf("Only alphabet is allowed.\n");
valid=0;
}
}while(valid==0);
I want the whole string doesn't have any numeric input.
You will have to process the entire string:
int i = 0;
for (i = 0; i < strlen(name) && i < 50; i++) {
if (!isalpha(name[i])) {
valid = 0;
printf("Please only use alphabetic characters!\n");
break;
}
}
Doesn't C language support regular expression like java does ?
so we can do it in java like this :
String test= "Any String even if 1 digit is in between";
Pattern p = Pattern.compile("[0-9]+");
Matcher m = p.matcher(test);
if (m.find())
{
System.out.println("Numeric is not allowed");
}
